Real power Parameter Addition in Electrical Connector - Revit Family

[Anto_Aravinth]

The electrical connector in our Revit families provides Apparent Power (kVA) and Power Factor parameters. However, our load equipment data is generally specified in Real/True Power (kW).

To accurately represent the design load in Revit, I would request that a Real Power / True Load (kW) parameter be made available directly at the electrical connector level.

This would help us to:

• Enter the equipment load directly in kW, as provided in the design/load schedule.
• Avoid manually converting kW to kVA using assumed or separate power factor values.
• Ensure the equipment load in Revit aligns directly with the approved electrical load schedule.
• Improve consistency and accuracy in panel schedules, load calculations, and equipment schedules.

For example, if an equipment load is specified as 100 kW with a Power Factor of 0.80, the apparent power can be calculated as:

Apparent Power (kVA) = Real Power (kW) ÷ Power Factor

= 100 kW ÷ 0.80 = 125 kVA

Therefore, if we could assign 100 kW directly to the connector as the Real/True Power value and specify the Power Factor as 0.80, Revit could derive the corresponding 125 kVA Apparent Power automatically.

The important point is that Revit's current electrical connector functionality is primarily based on apparent power (VA/kVA)

Your design input is 100 kW, but the connector workflow requires you to work with the apparent load (125 kVA) and PF.

So the engineer/BIM modeller has to do this conversion:

Design Schedule → 100 kW → PF 0.80 → 125 kVA → Revit Connector

Whereas your preferred workflow is:

Design Schedule → 100 kW → Revit Connector → PF 0.80 → 125 kVA

[HVAC-Novice]

In this thread I describe how I use 2 electrical connectors as a workaround.

the problem is that an electrical connector uses Apparent load (VA) and that is fine for circuit design. but for Lighting power density in spaces, we use Real Power (W). Revit for some reason doesn't differentiate (or take the power factor into account). If we assume a power factor of 0.9, the apparent power will be 11% higher than real power. Without my workaround I basically have to choose if my circuit design is 11% wrong, or if my lighting power density is 11% wrong. 

A solution would be to have the spaces account for the power factor to calculate the real power.