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circular spring

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Message 1 of 7
Anonymous
330 Views, 6 Replies
‎10-08-2019 08:50 AM
‎10-08-2019 08:50 AM

circular spring

When modelling a circular spring (modeling method: https://www.youtube.com/watch?v=ihM4uLzxeI0) I stumble upon a problem. As soon as the twist angle exceeds 9000deg, the sweep fails. Tried everything I could think of but no result.  Anyone has a suggestion? thx in advance!  FYI I should be able to input a twist angle of 10440deg.  I calculated this would keep a space of appr. 0.01mm between the inside of the coils. I use Inventor 2019.4.2

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Message 2 of 7
mcgyvr
Consultant
in reply to: Anonymous
‎10-08-2019 09:07 AM
‎10-08-2019 09:07 AM

Please attach the part



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Message 3 of 7
Anonymous
in reply to: mcgyvr
‎10-09-2019 12:47 AM
‎10-09-2019 12:47 AM

To make it complete, I'm not able to attach files to my messages... 

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Message 4 of 7
Anonymous
in reply to: mcgyvr
‎10-09-2019 09:56 AM
‎10-09-2019 09:56 AM

The files in attachment

veer.zip
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Message 5 of 7
TheCADWhisperer
Consultant
in reply to: Anonymous
‎10-09-2019 12:10 PM
‎10-09-2019 12:10 PM

I think there is a more efficient way of doing this in Inventor 2019.

I would probably use a Sweep with Twist and Animate Parameter.

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Message 6 of 7
Anonymous
in reply to: TheCADWhisperer
‎10-10-2019 05:38 AM
‎10-10-2019 05:38 AM

I've drawn it with sweep and a twist angle. I dont understand what you would do by animating the parameter...

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Message 7 of 7
johnsonshiue
Community Manager
in reply to: Anonymous
‎10-10-2019 01:29 PM
‎10-10-2019 01:29 PM

Hi! Animating parameters is a workflow in Inventor Studio, not in Inventor modeling environment.

Many thanks!



Johnson Shiue (johnson.shiue@autodesk.com)
Software Test Engineer
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