Zero Angle problem in sketch

[Anonymous]

Hello Everybody,

I am designing a cylindrical part that have different diameters from each side with a transition angle between 

depending on OD1/ID1/OD2/ID2 the transition angle will be 45 deg or zero

for example if OD1=OD2 I need to have this geometry below :

and if OD2<OD1 I need this geometry below : 

I wrote a rule that compares (OD1 with OD2) and (ID1 with ID2) and then change angle value (zero or 45 deg)

The problem is when I change OD1 and OD2 I have problems to change angle from zero to 45 deg, maybe Inventor does not understand in which direction he must turn the 45 deg and thus creating errors.
Could you please advise on this subject and how to resolve ?

Thank you

[bradeneuropeArthur · Accepted solution]

I use always a dummy line under for example 1 degrees

then I put the angle as formula like:

you need 0 degrees = parameterX

my angle is then from dummy line 1+parameterX

[Anonymous]

Thank you @bradeneuropeArthur  for your reply,

your suggestion solved part of my problem.(I added vertical line with angle = 90+parameter)
But for some reasons, when I try to change diameters the angle jumps to the other direction like image below :

Is there a way to make for example dimension B always greater than dimension A ?

or some sort of constraints to force point "b" to be always on right side of point "a" ?

Thank you

[bradeneuropeArthur · Accepted solution]

Always take less then Round value.

Like 89.235 degrees

[Anonymous · Accepted solution]

thank you @bradeneuropeArthur  for your reply

I solved it by using linear dimensions instead of an angle and it seems to work ( I will keep in mind not to use round values in the futur)

Thank you