Geodesic dome 3v

[Anonymous]

Hi, can anyone tell me if it’s possible to adapt this tutorial for a 4v dome into a 3v dome. I’ve trued adapting the 2v mesh by adding extra reference points linked back to the sphere radius and drawing my 3v triangle there but it doesn’t seem to work. Has anybody got any suggestions? https://youtu.be/m6VCOK0Op0k

[barthbradley]

Depends on what you mean by 3v. Don't all Geodesic domes use triangles, and aren't all triangles 3-sided (hence, a "triangle")? Isn't the difference between 1v, 2v, 3v and 4v, basically determined by the size of the triangles? 

[Anonymous]

I am trying to the same thing and I still don't have solution. How do you make an extra reference points, that you had to add for the 3V, show as an equal distance once you load it into icosahedron? 

[Ilic.Andrej]

---

@barthbradleywrote:

Depends on what you mean by 3v. Don't all Geodesic domes use triangles, and aren't all triangles 3-sided (hence, a "triangle")? Isn't the difference between 1v, 2v, 3v and 4v, basically determined by the size of the triangles? 

---

By 3v, I think she means "resolution".

[barthbradley]

if by "resolution" you mean "smoothness" of the spherical shape; then I concur.  

[Ilic.Andrej]

Yes. I'm just not very good at English

[Anonymous]

Yes, I mean the smoothness or on how many triangles are inside the big triangle of the icosahedron. Check out the video that the guy who opened the topic is referencing to. 

Anyway, I think i find the solution: when dividing the edge of the equilateral triangle for the 3v geodesic dome you need to specified normalized curve parameter to 1/3 for the first point and  2/3 for the second point. That way points will always stay on 1/3 of the triangle side once you load it into your icosahedron. 

[ToanDN]

http://www.byexample.net/library/illustrations/geodesic_dome_formula/

It's about the number of strut length.  1V means all struts have the same length, 3V means 3 different lengths, etc...

I doubt Revit can create the UV patterns strictly follow these criteria.  1V or random V maybe, but not specific 2V, 3V, etc.

[barthbradley]

What about a strutless geodesic dome? "zero-v"? 

...nevermind. I'm all v'ed out now. 

[Anonymous]

You are using the v wrong - it does not refer to the number or the length of the struts. 

Buckminster Fuller introduced the notion of nV  and it means the amount of division of an original triangle. 

Here is some reference about geodesic math.

http://www.salsburg.com/geod/geodesicmath.pdf

[ToanDN]

@Anonymous

Does something like the below work?

[Anonymous]

yes

[ToanDN]

Well with the new forum UI vee'ed up I am not sure to whom you replied to.  In case you replied to me, then what I did was using divided paths to control the spacing.  There is no need to use dimension parameters in such cases.

[barthbradley]

Okay @Anonymous; let's just cut to the chase here. It's been a few hundred years since I studied this in school, but isn't the fundamental distinction between 3v, 4v, 6v, etc. --- the size of the triangles?  This has always been my understanding. 

...I'm with you @ToanDN on this new UI. It was easier to follow the discussion with the old interface.  

...oh, and also @ToanDN, have you noticed how many old threads are now being responded to? I think it's also because of the new UI. Personally, I keep finding my navigated to a header page of thread topics from months ago.   

[ToanDN]

@Anonymous
Take a glance at the community feedback forum and see how folks rain on the new UI parade.

[ToanDN]

Okay I accepted being wronh. But how do you define what the "original" triangle of your model is?

[ct_studio]

I am wondering if this issue was resolved. I am trying to make what I believe is a 3v sphere:

 

 but I am not sure I even have the right classification.

Curious to know your thoughts, and thanks.

[ct_studio]

I am reading that the dome consists of both hexagonal and pentagonal panels.. which can be clearly seen in dome.jpeg

 But it apparently involves 16 sizes of panels which doesn’t seem like a true geodesic system?