Parametric arrays in families have one glaring flaw - that they have a minimum count of two. What I only want one instance of the nested family in one case and 15 instances in the next?
Is there any other way to accomplish this?
Any thoughts?
Solved! Go to Solution.
Parametric arrays in families have one glaring flaw - that they have a minimum count of two. What I only want one instance of the nested family in one case and 15 instances in the next?
Is there any other way to accomplish this?
Any thoughts?
Solved! Go to Solution.
Solved by barthbradley. Go to Solution.
Solved by ToanDN. Go to Solution.
Thank you, @ToanDN. Just as I had thought. What makes things a little stickier is that there already is a different piece at the end of the array, which give a minimum of three.
Thank you, @ToanDN. Just as I had thought. What makes things a little stickier is that there already is a different piece at the end of the array, which give a minimum of three.
Yes, and that visibility formula would interact with the array count (e.g. visibility parameter formula = array count<2)
Yes, and that visibility formula would interact with the array count (e.g. visibility parameter formula = array count<2)
A repeater? That one's harder to visualize
...BUT THANK YOU ANYWAYS MY FRIEND!
(yelling? no. Just inside joking with you. )
A repeater? That one's harder to visualize
...BUT THANK YOU ANYWAYS MY FRIEND!
(yelling? no. Just inside joking with you. )
And place the nested families on the points on the adaptive path?
And place the nested families on the points on the adaptive path?
Aaahhh!! NOW I know what @barthbradley meant when he talked about Repeaters!
Aaahhh!! NOW I know what @barthbradley meant when he talked about Repeaters!
Can't find what you're looking for? Ask the community or share your knowledge.