Sort a list containg more than one 2-member list

[scot-65]

Can't seem to find an appropriate thread in the archive...

I have a list that contains more than one 2-member list.

The format is '(frequency  name).

The first member in the 2-member list is a number. The second is a string.

The 2-member lists are already sorted via the second member.

(list

 (2 "Abc")

 (6 "Def")

 (1 "Ghi")

 (2 "Jkl")

)

[Using lambda], How do I sort using the first member?

(list

 (6 "Def")

 (2 "Abc")

 (2 "Jkl")

 (1 "Ghi")

)

Scot-65

[Kent1Cooper · Accepted solution]

(vl-sort '((2 "Abc") (6 "Def") (1 "Ghi") (2 "Jkl")) '(lambda (a b) (> (car a) (car b))))

returns

((6 "Def") (2 "Abc") (2 "Jkl") (1 "Ghi"))

[scot-65]

Thanks.
I was close.