mapcar querry
@vishshreevT578L wrote:
(setq a '(1 2 3 4 5) (1 2 3 4 5) In tutorials to add 1 to list a is (mapcar '1+ a) (2 3 4 5 6) but i want to add 2 to my list a please help
In this specific case, another rather simple way to do it is to just add 1 to each one twice:
Command: (setq a '(1 2 3 4 5))
(1 2 3 4 5)
Command: (mapcar '1+ (mapcar '1+ a))
(3 4 5 6 7)
But that approach would get cumbersome quickly if you need to add larger numbers to those in the list -- @Anonymous's suggestion in Post 2 is really the way to go, because the only change would be in the 2, and the rest of the code doesn't need to get any longer.
Hi
An another
(setq lst1 '(1 2 3 4 5)) (setq lst2 '(1 2 3 4 5)) (mapcar '(lambda(a b) (+ a b)) lst1 lst2)
@+
@patrick_35 wrote:
...
An another
(setq lst1 '(1 2 3 4 5)) (setq lst2 '(1 2 3 4 5)) (mapcar '(lambda(a b) (+ a b)) lst1 lst2)....
That results in (2 4 6 8 10), adding each number to itself. That result can be obtained more simply from those two lists:
(mapcar '+ lst1 lst2)
But to get what they're looking for -- adding 2 to each number in the original list [the equivalent of applying the (1+) function to each number as in Post 1, but adding 2 rather than 1] -- with this approach, the 'lst2' variable would need to be set to:
'(2 2 2 2 2)
rather than the same as 'lst1'.
[It seems to me that Post 2 is really the Solution to the original question in Post 1, and that Post 8 is not, but (however helpful it may be) is actually an answer to the different question in Post 3. But I'll suggest that @vishshreevT578L change the designations if that's correct, rather than do it myself.]
Hi
You are right to take me back and simplify the function because I did not think
The idea is just to show the addition of two lists, regardless of the numbers. Otherwise, I agree with what was previously proposed.
@+