Modeling Cable and Damping System in Robot

tau_oragami
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Modeling Cable and Damping System in Robot

tau_oragami
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Attached is a cross-section of a proposed cantilever roof section. I aim to support the end with a cable that extends over a central pier to the other side. How can I model the cable so that the tension is equal on both sides? Is there a way to model a pulley support at the top of the pier?

 

tau_oragami_0-1730311510742.png

 

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Rafacascudo
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Using "truss bars" type instead  of cables ,You can force the horizontal component of the 2 " cables" to be the same by setting a shear release on the mast top in the same plane of the mast and the 2 cables..

If the mast local axes are not aligned with the cable directions then you will have to adjust it with Geometry/properties/ gama angle

Rafael Medeiros
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tau_oragami
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In terms of defining the release, is this the correct procedure?

 

tau_oragami_0-1730340269388.png

 

 

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Rafacascudo
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that is the Releases dialog window , but as releases are set in terms of bar local axes  , you will have to mark Uy or Uz as released ,depending on which of these 2 axes is aligned with the 2 "cables" plane

Rafael Medeiros
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tau_oragami
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I created a simple example of what I am trying to accomplish. I linked two bars by a pin support and applied loads in opposing directions. I am still a bit unsure of the modelling procedure. 

 

tau_oragami_0-1730475529047.png

 

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Rafacascudo
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This is what I meant on my posts

 

 

Rafacascudo_2-1730547323358.png

 

No shear force on the mast on the released model , so all horizontal forces come from the 2 " cables"

Rafacascudo_3-1730547405558.png

 

Do the math and you will see that the cables horizontal components are the same

 

 

Rafael Medeiros
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Simau
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@tau_oragami  said in message 1:

How can I model the cable so that the tension is equal on both sides?

I think itā€™s not possible.

M. Agayr
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Rafacascudo
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In fact there is a way to to do it!!!

Rafacascudo_0-1730653339797.png

I changed the structure type on Geometry menu to Frame 2d to avoid unecessary instability warnings on non relevant directions to this model.

Then I edited the mast top geometry to simulate the cable around a pulley device . Cable angles became slightly different in this process ,compared to the original model

Everything was done with truss bars

Rafacascudo_1-1730654531215.png

Rafacascudo_2-1730654861973.png

 

Unreleased model would be the most common choice for this type of structure

 

Mast top node released for shear , my 1st suggestion  has the strongest point ,as a side effect, making the mast moment Zero all the way to the bottom as there is no shear on mast top. Mast axial force are way higher though.

But I think it would be hard to build that shear release on real life.

Pulley system , good exercise , but in this case/model geometry ,I donĀ“t see much difference compared to standard model . And never saw that also in real life.

 

Test model attached

 

 

 

Rafael Medeiros
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Simau
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Hi @Rafacascudo 

But I think it would be hard to build that shear release on real life.

Pulley system , good exercise , but in this case/model geometry ,I donĀ“t see much difference compared to standard model . And never saw that also in real life.

I agree

Very great approach to model a pulley.
Can be used in lifting systems

M. Agayr
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