If statement

[yes_and_no]

I have window trim profile at 3 y/n choices,

Profile = 2.5" (not a y/n, default)

Wide 3.5"

Wider 5.5"

My if and statement is not working,

Profile= if(and(wide, wider),(3.5", 5.5", 2.5")

[barthbradley]

.

Post a screenshot of your Family Types dialog box. 

=if(and(Parameter A, Parameter B), Value if True, Value if False))  

What the heck is the third value here?  =if(and(wide, wider),3.5", 5.5", 2.5")  

[David_W_Koch]

Does Wider always take precedence over Wide or Default, and Wide over Default?

If so, then perhaps this will do what you want:

if(Wider, 5.5", if(Wide, 3.5", 2.5"))

If not, you will need to explain what you are trying to do in words, and someone here can help you translate that into a formula.

[yes_and_no · Accepted solution]

• This is not good, this is EXCELLENT !!!