Conditional formula for YES/NO parameter

[luis_brionesalonso]

Hi, 

I've been having an issue that I cannot resolve regarding conditional formulas for YES/NO parameter. 

I have three YES/NO parameters: A,B, and C. A is only YES when a certain condition is met, B is a simple Tick Box (YES/NO instance parameter). What I want to achieve is the following: 

If A=NO then C=NO, if A=YES then C=NOT(B)

or

If A=Yes then C=NO, if A=NO then C=NOT(B).

Does anybody know how you could possibly write a formula for C so that these conditions are met?

[Luiscko]

I think the best way is create two parameters yes and no, one for AB and another for C, when you obtain your first result then you can apply one script to Dynamo pretty easy

[luis_brionesalonso]

I'm not sure I see how the Dynamo-script is applicable here. The parameters are meant to be used as visibility parameters in a detail family if it helps. The parameters have to remain seperate as well since the goal is to have parameter C=not(B) when A=YES and C=NO when A=NO.

A and B can vary independent from each other.

[barthbradley]

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@luis_brionesalonso wrote:

Hi, 

I've been having an issue that I cannot resolve regarding conditional formulas for YES/NO parameter. 

I have three YES/NO parameters: A,B, and C. A is only YES when a certain condition is met, B is a simple Tick Box (YES/NO instance parameter). What I want to achieve is the following: 

If A=NO then C=NO, if A=YES then C=NOT(B)

or

If A=Yes then C=NO, if A=NO then C=NOT(B).

Does anybody know how you could possibly write a formula for C so that these conditions are met?

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Huh??? Makes no sense. It reads like C is never on.  If A and B are checked, C is unchecked.  If A and B are unchecked, C is also unchecked. 

Maybe you mean this:

C=and(not(A), not(B))

[luis_brionesalonso]

As mentioned above, A and B are independent from each other. So there are four combinations, not two.

what I want to achieve:

If A=no then C=no, if A=yes then C=not(B)

So if A=yes and B=no then C=yes

If A=yes and B=yes then C=no

If A=no then C=no, whether B=yes or no

Hope this helps you understand.

[barthbradley]

Did you try the formula I gave you above?  

C=and(not(A),not(B))

[chunton]

Try this:

if(not(A), A, if(and(A, B), not(A), if(and(A, not(B)), A, B)))

[FAIR59 · Accepted solution]

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@luis_brionesalonso wrote:

As mentioned above, A and B are independent from each other. So there are four combinations, not two.

what I want to achieve:

If A=no then C=no, if A=yes then C=not(B)

So in formula-language: IF(not(A),A,not(B))

[luis_brionesalonso]

I'll try it out tomorrow, although I suspect that formula won't work since it reads as giving a YES value when A and B are NO and a NO value when A and B are YES, which is not what I am looking for. I think the formulas given below are the correct solution to my problem. 

[barthbradley]

Yep. It doesn't work with the conditions you spelled out in your second post.  I just threw that one out based on what you wrote in your first post:  "C" is OFF when "A" is ON or OFF.   Understandably, a little confusing.   Actually, the correct formula for that one would be: "C"=1>2 

[luis_brionesalonso]

Works perfectly, thank you.

[luis_brionesalonso]

It actually does work when you rewrite it to C=and(A, not(B)) since it should only be on when A is on and B is off in this case. Thank you for the suggestion.