What is the use of XYZ normal in NewFloor() method?

[Anonymous]

My floor type is like this:

when I use the xyz(0, 0, 1) to create a floor, the result is:

when I use the xyz(0, 0, -1) to create a floor, the result is the same:

No matter which XYZ normal I use, the result is the same.

How can I create a floor like this? Let the yellow on top.

I look forward to your reply, thank you very much！

Richard

[jeremytammik · Accepted solution]

Dear Richard,

Try to solve this in the user interface first, before researching a programming solution.

You may have to define a completely different floor layering with the yellow layer first (top) and the orange one last (bottom), inverting the order of the existing layering definition.

Cheers,

Jeremy

[Anonymous]

Dear Jeremy ,Thank you for your reply!

This problem can indeed be solved through the user interface.

I just don't understand where the difference between 

public Floor NewFloor(
	CurveArray profile,
	FloorType floorType,
	Level level,
	bool structural
)

and 

public Floor NewFloor(
	CurveArray profile,
	FloorType floorType,
	Level level,
	bool structural,
	XYZ normal
)

[jeremytammik]

Apparently, it was intended to switch the top and bottom face, just as you expected:

http://thebuildingcoder.typepad.com/blog/2014/03/creating-a-sloped-floor.html

Cheers,

Jeremy

[Anonymous]

Thank you for your kind answer！

I have benefited a lot from many of your articles. I believe that as I get more and more knowledge of the API, I will understand the problems that are confusing me now.

对于众多在Revit二次开发道路上的人们，您是一位非常可贵的良师益友。//For many people on the road of Revit's secondary development, you are a very valuable mentor.

Good luck!

[jeremytammik]

Thank you very much for your kind appreciation and the best of luck to you too!