AngleAboutAxis in C#

[vanlion]

Hi,

I'm trying to get the same result from the dynamo node vector.AngleAboutAxis in dynamo with the following code in C#. But the result isn't the same as you can see under the dynamo node and my C# results. Does anybode know how to do this in C#? 

// new XYZ from average point
XYZ pA = new XYZ(averageX, averageY, 0);  
XYZ pB = new XYZ(averageX-100, averageY, 0);

 XYZ res = pA - pB;

//Other vector from all points
foreach (XYZ d1 in coord)
{
   XYZ vv = res -d1;                               

   double angle = vv.AngleTo(res);

   double resultAngle = angle * 180 / (Math.PI);                              

}

[jeremytammik]

Please explain exactly what you are trying to achieve.

> Does anybody know how to do this in C#? 

'This' is not clear to me. 

[vanlion]

Hi Jeremy,

I already found how to do this in C#. In the picture below you can see how to translate the Vector.AngleAboutAxis in dynamo. With this diagram (in yellow) it is very easy to make the convertion to C#.

[dhanait_ajay13]

can you please share the code with me? how we can convert

[jeremy_tammik]

For me, it would be easier if you describe exactly what you are trying to achieve in pure geometric terms, since I am not familiar with the Dynamo node that you refer to. It is probably really simple and a standard operation, but which one?