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Hi, I've got a macro that I'm working on (which works well) except for 1 line which is trying to use an integer in a formula. The line is
Range("Z2:Z & lastRow).Formula = "=ISNUMBER(SEARCH(-" & MatTypeIdentifier & ",RIGHT(B2,4)))"
I've seen people recommend double quotes but that results in a compile error in the Inventor VBA. Anyone have any suggestions? Seems there's gotta be a way which allows this to compile.
Solved! Go to Solution.