Just not sure...
Defining a material properties...If I provide Young Modulus and Poisson Ratio, but I left 0 for the Shear Modulus...
Is Inventor smart enough to calculate and derive it automatically (from E and nu)?
Thanks!
Solved! Go to Solution.
Just not sure...
Defining a material properties...If I provide Young Modulus and Poisson Ratio, but I left 0 for the Shear Modulus...
Is Inventor smart enough to calculate and derive it automatically (from E and nu)?
Thanks!
Solved! Go to Solution.
Solved by imajar. Go to Solution.
You define the Shear Modulus (if not already defined).
All Material Properties are library definitions.
But this number is irrelevant for Linear Elastic Static Stress calculations as it is not used.
Only Young's Modulus (Modulus of Elasticity)
Density (and only if Gravity is enabled)
Yield Strength
(Tensile Strength if brittle material as set to use in the analysis.)
Other properties become important if going into other analysis tools like Inventor Nastran.
You define the Shear Modulus (if not already defined).
All Material Properties are library definitions.
But this number is irrelevant for Linear Elastic Static Stress calculations as it is not used.
Only Young's Modulus (Modulus of Elasticity)
Density (and only if Gravity is enabled)
Yield Strength
(Tensile Strength if brittle material as set to use in the analysis.)
Other properties become important if going into other analysis tools like Inventor Nastran.
Hi. Thanks.
If I define the Young Modulus and Poisson Ratio I have not to define the Shear modulus as it is calculated with the first 2 imputs (Young Modulus and Poisson Ratio).
So my question was:
If i leave 0 for shear modulus , will the software be able to calculate it automatically? I presume yes. Am I correct?
Hi. Thanks.
If I define the Young Modulus and Poisson Ratio I have not to define the Shear modulus as it is calculated with the first 2 imputs (Young Modulus and Poisson Ratio).
So my question was:
If i leave 0 for shear modulus , will the software be able to calculate it automatically? I presume yes. Am I correct?
Check out the documentation:
"If any one of E, G, or NU is blank, it will be computed to satisfy the identity E = 2(1 + NU)G; otherwise, values supplied by you will be used."
Check out the documentation:
"If any one of E, G, or NU is blank, it will be computed to satisfy the identity E = 2(1 + NU)G; otherwise, values supplied by you will be used."
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