Stress Analysis on Anti Roll Bar

[CherylR001]

I'm looking for some help on doing some stress analysis on a Anti Roll Bar and I was wondering if it was even possible.

I have attached a screen shot of the assembly and another of where I want it to displace to. I need to displace it to where the transparent bar is. The 2 horseshoe shaped brackets are static as is the opposite end to the yellow surfaces. The turning axis of the ARB is the center axis of the bush. I need to find a way to apply force to displace the yellow surfaces tangentially to the axis of the bush. 

Thanks

Cheryl

[j.palmeL29YX · Accepted solution]

I hope I understand your issue right.

In most cases we add forces and moments and want to know stresses and displacements. This is shown in the first half of >>this video<< . A force of 500 N results in a displaceent of about 13 mm.

But we can do it also the other way, shown in the video starting at about 1:33.

We add a fixed constraint with a given displacement of 13 mm. After running the simulation we find a reaction force at this "moved" constraint - about 500 N.

I hope you can use this priciple also in your project.

[johnsonshiue · Accepted solution]

Hi Cheryl,

For Inventor FEA, you can apply loads and get the deformation, not the other way around. I think you may need to apply force along the yellow portion of the bar, pointing downward. The exact magnitude would require some trial and error to get to the desirable deformation.

You may also want to look into Inventor NASTRAN, which can perform non-linear analysis and more.

Many thanks!

[JDMather · Accepted solution]

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@johnsonshiue wrote:

For Inventor FEA, you can apply loads and get the deformation, not the other way around.

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Actually, you can enter a Prescribed Displacement and get the resulting Reaction Forces as described by @j.palmeL29YX , as long as you stay within the usual rules for Inventor FEA (stay within linear elastic range, relatively small displacement, "slowly" applied load...).

[j.palmeL29YX]

Attached a fictitious example. 

For the right end I have choosen a displacement of 5 mm - after running the simulation we see a needed force of 435 N.

In a similar manner you can choose any value for the displacement, but of course the used material must have appropriate properties to bear the displacement (note the safety factor).