Frame Member in Drawing View

[Anonymous]

Hi,

I have a frame member which has a Mitre (45) cut on one end of the member and a mitre (45) cut on the other end but on a different face

How do you place this member in a drawing (.idw) showing both mitre cuts and then dimensioned?

I attached an .ipt part (same dimensions as the Frame Generator member)

The part is 2013

Thanks

[Anonymous]

Could someone post a drawing on how they would place and dimension this member in a .IDW Drawing?

Thanks

[mdavis22569]

not sure if you do first angle, or 3rd angle ...but here is an example

[Anonymous]

Thanks Mike

Yes i am not sure how to show the 2 different mitres. Will play with more

Thanks

[mdavis22569]

I showed you both views with the different miters in each ....this could have it made for you

[Anonymous]

Could you please attach the drawing. I am using 2013

[mdavis22569]

I can make you a pdf ... I'm on 2016 and 2017 (sorry)

you want to show where the cut starts, and the angle, because you may not always miter on a 45 

[Anonymous]

Hi Mike 

A PDF would be appreciated

I attached a screenshot of the actual sizes. I not sure i have shown where the dimensions are most important (I think)

[mdavis22569]

here ya go

[Anonymous]

Thanks Mike

Could you please have a look at the image i posted last.....the dimensions are correct for this piece. Is this dimensioned wrong?

Thanks

[mdavis22569 · Accepted solution]

the length is wrong ... you're at 1000, and it should be 640

I've attached a new PDF

[Mark.Lancaster · Accepted solution]

@Anonymous

Not sure if you are a student or not but dimensions should always be based on the standard that your company has in place.

However a few things..

The dimension of 88.9 should state 88.9 SQ to indicate the tube is square and all sides are the same/equal.

Remove both of the dimension 462.2..  You are using first angle projection in your drawing so you are trying to measure a linear distance on one side of the frame member to another edge on the other side.  Think about this part in your hands.  How would you measure that as a linear dimension?  Remember dimensions are being provide on a document so someone can make and inspect the final product.  It would be very hard to measure this 462.2 dimension.

Remove one of the 640 dimensions.   There's nothing wrong with the secondary one but its called over-dimension or duplicate dimension.  Its like when your sketching in Inventor and it tells you "adding this dimension will over-constrain the sketch".

Also I looked at your part..  The miter ends you could've just done with an extrusion cut instead of a doing a split.