Distributed Loads

[Anonymous]

Hello there

Below I have attached a geometry of aluminium box on which there are two loads are acting one on the bottom surface and the other one is on the side surface. The box is filled with a block of magnets weighing about 12kg which is about 118N/m the magnetic force is acting in x-direction which is about 280N. If I were to apply these loads as distributed loads should I multiply the loads with the whole surface area or only through the length

Based on the data the dimensions of the magnet holding box are fixed as follows:
Outer length = 230mm  Inner height=118mm
Total Width= 78mm   Inner width=72mm 
Total height= 122mm  Wall thickness=2mm

Inner length = 223mm

Thank you for your help

[JDMather]

What version of Inventor are you using?

Is there a reason that you attached STEP file rather than the original *.ipt file?

Is there a reason that one side wall is 2mm thick while the other side walls are 4mm thick?

Is there a reason that the bottom is 3.5mm - different thickness than the walls?

Aluminum is not magnetic - where is the part that the magnetic force will interact with?

Where are the constraints located?

You simply enter the Total forces and the constraints.

[Anonymous]

Below I have attached an assembly file in which these boxes are held at a certain height since both the boxes are filled with the magnet blocks there the magnetic force is due to interaction between these blocks.  The magnetic field of the blocks is used for controlling the magnetic nanoparticles that are used in drug dosage inside a human eye. The variation in wall thickness is to get an optimum magnetic field on the testing side. if the distance between the human head and magnet block is more than 4mm then the impact of the field is affected greatly to avoid since we have a tolerance of 1mm for blocks placed inside the box the left side of the box has a limited wall thickness of 2mm. whereas the bottom thickness is limited to 3.5mm as the height of the magnet block.

I have also attached the screenshot of boundary conditions applied as per my understanding

[Anonymous]

Sorry for the stp files I don't have inventor tool as I am using mac right now

[lena.talkhina]

Hello @Anonymous !

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