You can't.
You can do it with math (integral)
Admaiora
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Hi,
Equation Curve. I guess I can't do that. 🙂
iLogic, maybe.
Admaiora
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I think that could be the solution. The dimension would be better. Maybe in the future?
((20)^2*(1-(t/40)^2))^(1/2)
video link
Yes, ilogic is an interesting sight. 🙂 I don't know what such a code would look like. 🙂
Just an idea.
The code and setting can be improved (angles, axis, etc)
Admaiora
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Hi,
it's nice. Why don't the lengths match 1: 1? Is it rounding?
I was still trying the formula, but I think I still have a mistake there. I can't give Accepted to myself or you. I need those 5 mm. Yes, your ilogic is nice, but it affects the whole ellipse. The customer needs 5 mm for drilling.
I tried the dimensions from the customer and I don't understand why I have to put 4.8 into the formula to have a length of 5 mm. I thought the box was length.
As I said the code and model needs to be processed .
It reds the perimeters, but you can subtract the linear edges to obtain the length of the angular arc.
Admaiora
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Do you need it for a practical purpose (drilling)?
Can't you work around it by creating a projected 3D sketch?
See my attached (IV2018) file, does that help?
Niels van der Veer
Inventor professional user & 3DS Max enthusiast
Vault professional user/manager
The Netherlands
Hi,
yes, i think this may be enough for the customer. It didn't occur to me. It's very simple and practical. Yes, I think this is the solution. Yes the length is accurate. Thank you very much everyone.