Is it possible to reference the current value of one joint in the formula of the other?
I have these two sliders, the one on the right is rigged to move twice as far as the one on the left.
I'd like to have the slider on the right move as some coefficient times the cosine of the movement on the left. i.e.
10 * Cos(a) (a is the displacement of the left)
Is it possible to reference the current value of one joint in the formula of the other?
I have these two sliders, the one on the right is rigged to move twice as far as the one on the left.
I'd like to have the slider on the right move as some coefficient times the cosine of the movement on the left. i.e.
10 * Cos(a) (a is the displacement of the left)
I am returning your model with a different name. Using parameters I have demonstrated how to add a parameter to the motion of the bars. If you right click on the Left joint and choose to "Animated the Model" you will see that Rod:2 will move twice as fast as Rod:1. I could not use your formula since the COS of a length makes no sense to me. Using my parameters idea you can try to figure out the math part.
John Hackney, Retired
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I am returning your model with a different name. Using parameters I have demonstrated how to add a parameter to the motion of the bars. If you right click on the Left joint and choose to "Animated the Model" you will see that Rod:2 will move twice as fast as Rod:1. I could not use your formula since the COS of a length makes no sense to me. Using my parameters idea you can try to figure out the math part.
John Hackney, Retired
Did you find this post helpful? Feel free to Like this post.
Did your question get successfully answered? Then click on the ACCEPT SOLUTION button.
This doesn't seem to solve the problem, though. All that matters is that cos(a) is non-linear and your solution 2*a is linear.
Try to do cos(a) whether it makes sense or not to you and you will see the problem.
This doesn't seem to solve the problem, though. All that matters is that cos(a) is non-linear and your solution 2*a is linear.
Try to do cos(a) whether it makes sense or not to you and you will see the problem.
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