Angle in Isometric View

[Anonymous]

Hello, I am new in AutoCAD. I am trying to make a angle in isometric view. I have a 2D front view and trying to make its isometric view. The front view is added here (File name: Angle.png). I have tried it several time to make the proper angle. But, it is vain.

Can anyone please tell me how can I create this angle? 

[GrantsPirate]

Locate the endpoints and connect those with a line

[Anonymous]

Sir, Thank you for your reply. But how can I find those end points? 😞

[leeminardi]

A 60° line has a horizontal displacement of 1 and a vertical displacement of sqrt(3) = 1.732...

Therefore, from point A go 1 unit in a direction of -30° and then vertically up 1.732. Connect these two points to get the isometric projection of a line at 60°.  For point B go 1 in the 150° direction (up and to the left) and then 1.732 vertically up. 

When drawing lines that are not parallel to a principal axis you will need to determine the angle by using the horizontal and vertical components of its slope and not the angle

[Anonymous]

Sir, I am doing this. 😞

[leeminardi · Accepted solution]

And what you are doing is wrong!  YOu are creating a line at 60° up and to the right which is not the angle for an isometric view.  The second line you create is at 30° up and to the left.  Again wrong.  It doesn't sound like you took the suggestion I presented in my last post.  You cannot use true angles in an isometric.

Try the following, create an isometric drawing of a perfect cube and draw lines between opposite corners as shown below.  The red and green lines are at an angle of 45° on THE REAL OBJECT but are not at 45° in the projection.  The red and green lines are the same length on the real object but not in the isometric drawing.

[SEANT61 · Accepted solution]

Another way to process the isometric angles is via construction geometry.  I arbitrarily chose some dimensions not provided, but the general idea is still valid.

[Anonymous]

Sir, I have done this! 

[SEANT61]

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@Anonymous wrote:

Sir, I have done this! 

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And you did well.  Those are the angles that should result.

[Anonymous]

@SEANT61  sir, I want to show 60 degree in isometric view!

[SEANT61 · Accepted solution]

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@Anonymous wrote:

@SEANT61  sir, I want to show 60 degree in isometric view!

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No, you don't.  An angle of 60 degrees in an orthographic projection will not be 60 degrees in an isometric projection.

[Anonymous]

@GrantsPirate , @leeminardi , @SEANT61 , Thank you sir. 🙂

[j.palmeL29YX · Accepted solution]

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@Anonymous wrote:

Sir, I have done this! 

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I'd prefer to use the solution shown by @SEANT61 in post No. 7 and would suggest you to do so too. This is an exact construction. You use a rounded numerical value. Maybe this lack of precision is akzeptable for you at the moment, but this inaccuracy can cause problems in the future.