Hello!
How is kF factor (EC3-5, fig. 6.1, p. 26) calculated in Detailed Design of Member Verification of Steel/Aluminium Design?
I was veryfying results from Ex. 9.2 (Arya, C. (2009) Design of structural elements, pp.389) for web buckling of an UB356x171x45, sitting on 125 mm bearings on both sides. Given ss=125mm and hw=332,6mm, the kF should be 4,25 (see the link above for the calculations).
In RSAP, however, given ss = 12,5 cm the kF becomes 2,75. I was fiddling with numbers and it seems to me as if RSAP is using hw = 100 cm (if indeed the expression given in the beginning is used), because the value of ss = 37,5 cm gives the kF = 4,25 (see the picture below) that I was trying to attain in the beginning.
This makes LamF and therefore Xf factors and ultimately FRd significantly different (handcalculations for ss=125mm give FRd=237,6kN). What am I missing here?
