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Tension in Link Bars

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Message 1 of 17
Mustafa_AlNajmawiNA4QJ
744 Views, 16 Replies

Tension in Link Bars

Hi All,

 

I have a project which is an enormous diaphragm wall. The panels are 3m in width. The reinforcement does not extend into the adjacent panels, therefore the correct way to model is to apply a linear release to the edges. After trying that i noticed that moment was still being transferred to the adjacent panels. Therefore we decided to model the panels with a 20mm gap and connect them with a linking beam to reduce the differential displacement. 

 

The problem is, some link beams have high tension on them, which is incorrect. Looking at the nodal displacements and the forces, there shouldnt be any tension on these beams. 

 

I have attached screenshots to show this

 

Mustafa_AlNajmawiNA4QJ_0-1711366680380.png

 

Mustafa_AlNajmawiNA4QJ_1-1711366707147.png

 

Mustafa_AlNajmawiNA4QJ_2-1711366957511.png

 

 

Mustafa_AlNajmawiNA4QJ_3-1711367112140.png

 

 

@Rafacascudo 

16 REPLIES 16
Message 2 of 17

"The problem is, some link beams have high tension on them, which is incorrect. Looking at the nodal displacements and the forces, there shouldnt be any tension on these beams. "

 

Not really  . If you look carefully the nodal Ux displacements are perfectly compatible with the bar tension forces. Having a closer look at the bar of your picture which shows a 803 kN axial force , we have

 

Rafacascudo_0-1711457175153.png

following the formulas for Stress and strain below

 

Rafacascudo_1-1711457277962.png

Doing the math we have

Epsilon(strain) = Delta L/ L= (0,633596477-0,632966383)/20 =0,000031505

 

P/A(Axial stress) = E x Epsilon

P = A x E x Epsilon 

P = 750000 x 34000 N/mm2(MPa) x0,000031505 =803377 N = 803,4 kN

, which is exactly the value you will get if you increase the decimals for force results in RSA

 

The linking bars you chose are very stiff and even very little displacement induces high axial forces in these bars and they are also transmitting moments as there are no releases on these bars

Have you tried linking these walls only with a single Ux rigid link??

Rafael Medeiros
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Message 3 of 17

I will try to reduce the stiffness, the only reason we modelled those link beams is to be able to look at the out of plane shear, so your advice is to model rigid links which are only restrained in the UX?

Message 4 of 17

the whole idea is to not allow any tension between the panels, compression yes but tension no
Message 5 of 17

Then , you have to link them with truss  "compression only" bars which will make the analysis nonlinear

Rafael Medeiros
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Message 6 of 17

i agree, but in this case i will not be able to see the shear force on the member, is there a way to make it compression only and view the shear?

Message 7 of 17

Yes ,

Use regular bars and then use bar releases and on the unidirectional tab set the diection Ux+ or Ux- that will allow only compression on these bars.

Don't forget to fully release your moments ( Ry and Rz) on both bar end nodes

I didn't understand why you are using 2 bars. I would use just 1 bar to simplify the model

 

Rafael Medeiros
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Message 8 of 17

so if i wanted to release it in tension and keep it compression only, to do this in the image below

 

Mustafa_AlNajmawiNA4QJ_1-1711469170101.png

and in the member tab, release the rotation??

Message 9 of 17

Normally you will need to release the unidirecional Ux just in one of the bar ends. Ux+ or Ux- will depend to where the bar Local X axis is pointing. Just make sure all bars have the exact same local axes , so you can assign the same release label type to all your bars. You can adjust the Local x direction on Geometry/properties/Local member direction.

And then , just try with Uz+ or Uz- and check if the model behaves the way you want(compression only)

For the rotation , yes ,on the member tab on the nodes close to the both walls

Rafael Medeiros
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Message 10 of 17

Hi Rafa,

 

I tried this solution but no matter what i do it is not converging,

 

i have attached the model

Message 11 of 17

Some remarks on your model .

1- You cannot ignore some warnings and never ignore an error(red text) . There was a warning I never had , " finite elements do not belong to any panel" . I selected them , selected their nodes and deleted them all. With that the inchorerent mesh error also disappeared.

2- As soon as you get a mesh you are satisfied , freeze it !!! Otherwise RSA will always rebuild the mesh again and again wasting analysis time every time you run the model

3- Your mesh in the upper part of the strucuture was not good. I changed the meshing method and some parameters to give me always square FEs.

4- As I told you before Unidirectional Ux release is needed only in one of the bar ends .Setting it on both ends was causing an instability warning on Ux direction

 
 

uni release.jpg

5- In a nonlinear analysis only self weight load case and the combinations are important as the other single cases like , wind , water , soil will never occur alone. And in your case ,as it is and underground structure , even the self weight will never occur alone . So I set all the single cases to be auxiliary. I ran the model only for the 2 combinations

 

6- I used the nonlinear settings below to make it converge . Sometimes it is better to set just 1 increment(Official support advice)

Rafacascudo_2-1711547834568.png

7- In job preferences , Structure analysis always leave the method on automatic  , because some of the methods do not report all the instabilities that may occur ( also from official support)

 

Model attached

 

 

Rafael Medeiros
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Message 12 of 17

Hi Rafa,

 

Could you send me a screenshot of the mesh settings you have used, unfortunately i do not have access to winrar so cannot unzip the folder. Could you compress it using standard windows compression?

Message 13 of 17

I am not with computer but meshing options are

Coons

Squares on square contour

FEs quadrilateral 

All these 3 settings set to " forced" option.

Mesh the 3 perpendicular walls 1st . Then mesh all panels of the large front wall. And do not forget to freeze them all.

I will send the model later.

Rafael Medeiros
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Message 14 of 17

Thanks Rafa,

 

I managed to sort it out,

 

Just a quick question, some of the link bars have compression on them, and the rest have zero axial force, i am assuming this is due to the non linear analysis which redistributes the tension to other members. The problem now, i see that the out of plane shear on the members is zero. 

 

I made the moment release only in one end and the shear has transferred correctly

 

Do you have any other suggestion 

Message 15 of 17

That is correct , if both sides are moment released , then there can be no shear on the beam if there are no loads on the span

 

Model attached

Rafael Medeiros
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Message 16 of 17

And regarding the bars that don’t show any axial force? Can you please explain that
Message 17 of 17

Bars with zero are those where their end nodes are translating on opposite direction and  therefore they would be in tension if Ux had not been released unidirectionally on one of its nodes

Rafael Medeiros
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