Hello,
I can’t explain the fundamental period of this structure by hand calculations.
I thought its dynamic behavior was a single degree of freedom system (cantilever beam).
Mass in the top : 19555059 kg (very similar to RSA)
J (25 circular R.C. columns 1 m diameter) : 1.2265 m4
E : 4000000000 daN/m2
L : 9 m
T = 1,9542 s (2 π √ M/K)
RSA calculate 0,63 s.
Thank you for your answers.
Solved! Go to Solution.
Hello,
I saw these differences between the model and the hand calculation (maybe you can tell me different):
1. as I can see, the behaviour is not a cantilever one, but I would say your stiffness should be 12EJ/L^3
2. The mass is not only on the top but also you have the mass of the columns.
3. I don't think is a rigid diaphragm.
4. The J of the columns is different from the one you have used.
Thank you for your answer.
Here’s my remarks:
Thank you.
I made a mistake in the mass in the top.
Mass in the top is 1563961 kg (not 19555059 kg ).
But, I’m still far from RSA solution.
Here’s my calculations:
Surface: 3601,76 m2
Dead load purlins: 43,8213 daN/m2
Dead load concrete slab 10 cm : 250 daN/m2
Live load parking: 234x0,6 = 140,4 daN/m2
Mass in the top: 3601,76x(43.8+250+140,4) = 1563961 kg
K= 3EJ/l^3 = 3x400000x1.2265/9^3 = 20190329 daN/m
T = 2x3.14x(1563961/20190329)^0.5 = 1,7478 s
RSA: T1 = 0,63 s
I still don’t consider column mass (441562 kg), which vibrate with a smaller period.
Is that the only reason of this difference?
Ok I found the issue.
It is all fine, you forgot to divide per g=9.81m/s2
What you find was kg / (kg/m2 * m4 / m3) = m
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