Hi all,
I have a question regarding user sections. in particular to bending/deflection, can you correct the angle to get the correct deflection.
See this simple section:
2 the same profiles, 100mm wide, 20mm high en thickness 3mm. left is under an angle of 35 degrees.
both are loaded with a load of 1kN/m1. but the deflection of the section with an angle is way different than the normal rectangular one.
my question now is, can i change an angle somewhere to get vertical deflection of profile under an angle?
(i need to check the vertical deflection).
all files including .dxf with profiles are attached.
thanks in advance
gr Edward
Solved! Go to Solution.
Solved by Krzysztof_Wasik. Go to Solution.
Not graphically. Best you can do is create nodes along bar lenght(use divide tool without dividing the bar) and check the nodal displament table
Rafael Medeiros
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As Mr. @Rafacascudo said, not graphically.
You can get the deflection components in the global directions (ux,uy,uz) from Results menu > Deflections.
You can find the exact deflections for each bar in the global directions.
For example: Bar No.(2) for the 2nd load case.
The local deflection in the pic = 1.133 mm.
In the table you can find that: Uy= 1.132 & Uz= 0.051 mm.
The total local deflection = Sqrt [ (Ux^2) + (Uz^2) ] = 1.133 mm exactly.
Muhammed Mamdouh (OPERA)
Structural Engineer, Instructor
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thanks for your reply.
I did a second check on these profiles by copying them(bar 3,4). an gave them in the properties the gamma angle of 35 degrees.
it seem's that when i read the maximum deflecton i have to convert the displacement values with the angle i used. See difference node 11 versus bar 3.
so it would be easier to just add a node in the middle for the correct displacement. is this true?
@Krzysztof_Wasik do you know if this is on the wish list? to have an user defined section with the correct deflection?
thanks in advance
gr Edward.
Hi @1234eddie
Bar deflection table presents deflections in bar local system of coordinates.
If you want to present beam (rotated around local x) deflection in global system of coordinates you should define intermediate nodes along beam and open nodal displacement table. (as you have noticed in your post)
In theory when we have bidirectional bending we analyze superposition of bending in principal section axes/planes. This is deflection Robot presents in deflection table. UY (deflection for bending in xy local plane) UZ (deflection for bending in xz local plane) and U(total) as both bending effects superposition.
thanks for your reply. it's clear for me know.
@Muhammed.OPERA and @Rafacascudo also thanks for your help.
gr Edward
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