CLADDING AND LOAD DISTRIBUTION

[BertelliMarco1095]

Dear all,

I use the cladding feature froms its addition in robot and is very usefull.

Today I was designing a rectangular slab with in the cernter a circular hole. I added a rectangular cladding and then a circle: you see on the screen that the circle forms an hole on the cladding. after the calculation if I look the the load ridistribution, i see that the hole is not considered! if I check the reaction the give the same result!

is this a bug or my procedure is worng? PLease find attached the example file.

[Anonymous]

Hello,

You didn't add the RSA-file to your question so I hope I did understand your question correctly.

I think you must ad the whole in your cladding as well.

greeting,

Henk Boelens

[Rafal.Gaweda]

It should work. If not please attach example.

[BertelliMarco1095]

now the file should be attached

[Artur.Kosakowski · Accepted solution]

The distribution algorithm is not capable of correct detection of openings that stretch up to the edges of a cladding itself. You should either create two claddings and no opening or reduce its size.

If you find your post answered press the Accept as Solution button please. This will help other users to find solutions much faster. Thank you.

[BertelliMarco1095]

ok

thanks very much

[Anonymous]

Hi

how did you get the load distribution pattern to display like that?

[Artur.Kosakowski]

[Anonymous]

Wow, that was a fast reply!!

Thanks, knew it would be something simple.

[Anonymous]

hey,

I am having problems with load distribution on the inclined roof, I added a load on the cladding but it is not distributed on the pannels. I put the load distibution in the right direction as seen in the attachement. It is working for the cladding on the columns.

Regards,

Gabriel Habib

[Anonymous]

Hey,

This is a other photo too.

Regards,

Gabriel Habib

[Rafal.Gaweda]

Robot file please.

[BertelliMarco1095]

I only aswered to another user that have problems

[Anonymous]

hey,

thanks for the reply but I figured it out. the cladding were not placed correctly at the nodes.

Regards,

Gabriel Habib

[Anonymous]

I dont know why the Cladding Load distribution is hidden. Please help me out

[Anonymous]

Q2 .Can some one help me to find a way to distribute the load equally on for sides?

Equally on four sides not 45 degree.

[Artur.Kosakowski]

Hi @Anonymous

The cladding load distribution option is based on the principle of assigning load from the tributary area which 'belongs' to given 'supporting' element. The kind of the load you described is also available in RSA. It is applicable to bar elements and doesn't require any cladding definition:

 

If one or more of these posts answered your question, please click Accept as Solution on the posts that helped you so others in the community can find them easily.

[kmmdD66ZQ]

Hi @Artur.Kosakowski 

Is RSA not able to distribute load of a simple cladding with a uniform planar load correctly? Or is there anything I am doing wrong in this matter.

I tried adding RSA file but it won't let do that.

Thanks in advance.

[Krzysztof_Wasik]

Hi @kmmdD66ZQ 

Load distribution procedure assigns cladding area to defined beams.

In your case.

Then loads applied to assigned area are transferred to the corresponding beam.

[kmmdD66ZQ]

Hi @Krzysztof_Wasik 

I am aware of the way of distribution, but is it possible to distribute the load correctly without needing to calculate the distribution by hand and applying it as a lineload. 
25% of the load should be placed on beam 2 in your and my case.