Good morning,
The question is not for me, but i think the answer is yes.
I have a similar spreadsheet for non-linear supports and the workflow is basicly the same.

I have non-linear functions for UX, UY, UZ and so on and i've tested the following code:
Private Sub CommandButton1_Click()
Dim RobApp As RobotApplication
Set RobApp = New RobotApplication
RobApp.Interactive = False
Dim i As Integer, j As Integer, k As Integer
i = 1
j = 0
Dim aux As Double
Dim myBarRD As RobotBarReleaseData
Dim mylabel As RobotLabel
Dim mynlm2positive As RobotNonlinearLinkParamsCustom
Dim mynlm2negative As RobotNonlinearLinkParamsCustom
Dim mynlmCS As RobotNonlinearLinkParamsCustomSegment
Dim myNLM As RobotNonlinearLink
Do While Cells(9 * i - 6, 1) <> ""
Set mylabel = RobApp.Project.Structure.Labels.Create(I_LT_BAR_RELEASE, "apoio_no_" + CStr(Cells(9 * i - 6, 1)))
Set myBarRD = mylabel.Data
' Direction UX
If Cells(9 * i - 6, 3) + Cells(9 * i - 5, 3) + Cells(9 * i - 4, 3) + Cells(9 * i - 3, 3) + Cells(9 * i - 1, 3) + Cells(9 * i, 3) + Cells(9 * i + 1, 3) + Cells(9 * i + 2, 3) <> 0 Then
Set myNLM = RobApp.Project.Structure.Nodes.NonlinearLinks.Create(CStr(Cells(9 * i - 6, 1)) + "_UX")
myNLM.SetCurveType I_NLCT_CUSTOM
Set mynlm2negative = myNLM.GetParams(2)
Set mynlm2positive = myNLM.GetParams(1)
myNLM.SetParams mynlm2negative, 2 'in order to set symetry to false
' MsgBox myNLM.Symetry
' Define positive values of non-linear diagram
j = 1
For k = 9 * i - 2 To 9 * i + 2
If Cells(k, 3) = "" Then Exit For
Set mynlmCS = mynlm2positive.New()
aux = Cells(k, 4).Value * 1000
mynlmCS.OriginPoint = Cells(k, 3).Value / 100#
mynlmCS.Expression = aux
mynlmCS.Constant = False
mynlm2positive.Set j, mynlmCS
j = j + 1
Next
myNLM.SetParams mynlm2positive, 1
' Define negative values of non-linear diagram
j = 1
For k = 9 * i - 2 To 9 * i - 6 Step -1
If Cells(k, 3) = "" Then Exit For
Set mynlmCS = mynlm2negative.New()
aux = Cells(k, 4).Value * 1000
mynlmCS.OriginPoint = Cells(k, 3).Value / 100#
mynlmCS.Expression = aux
mynlmCS.Constant = False
mynlm2negative.Set j, mynlmCS
j = j + 1
Next
myNLM.SetParams mynlm2negative, 2
' assign non linear model to support
myBarRD.EndNode.NonlinearModel.Set I_DOF_UX, CStr(Cells(9 * i - 6, 1)) + "_UX"
RobApp.Project.Structure.Labels.Store mylabel
Else
End If
Dim selectionBars As RobotSelection
Set selectionBars = RobApp.Project.Structure.Selections.Get(I_OT_BAR)
selectionBars.FromText CStr(Cells(9 * i - 6, 2))
RobApp.Project.Structure.Labels.Store mylabel
RobApp.Project.Structure.Bars.SetLabel selectionBars, I_LT_BAR_RELEASE, mylabel.Name
i = i + 1
Loop
RobApp.Interactive = True
Set RobApp = Nothing
MsgBox ("The End!")
End Sub
In the example it is applying the non-linear model only at end-node and non-linear function for UX but i think you can get the picture. Sorry for the lazzy code...
The result of this code is something like this:

Kind regards