Revit "IF" statement with visibility parameter

[ahuntPTQKR]

Hi

I was wondering if anyone would happen to know what the correct boolean expression is for the following "IF" statement to set a visibility parameter to off/none-visible (where i've type "<output false/off>" below)

if(parameter1, parameter2, <output false/off>)

I've tried typing the following:
(which don't work)

if(parameter1, parameter2, 0) 
if(parameter1, parameter2, no) 
if(parameter1, parameter2, false) 
if(parameter1, parameter2, off) 

[RDAOU]

@ahuntPTQKR 

It works as follows: if(Syntax, True, False) .... ie: if(parameter1> 1000, 2>1, 1>2)

Depending on the type of parameter1  and in simple conditions where only On or OFF is applicable, you do not need the IF you just need the TRUE part of the condition

Example:

• when parameter1 is a length parameter and you want to make to turn visibility on for a certain length value, either of the following works:
  1. parameter1 >5'
  2. and(parameter1 > 5', parameter1 < 10')

• when parameter1 is another Yes/No parameter, you just type in the formula parameter1 (meaning when parameter1 is True/ON, the visibility parameter will be also True/ON and vise versa)

If parameter1 is a Text parameter => it is a bust. Text can only be used as output, you cant use Text parameters as Conditions in formulas

[barthbradley]

Look into embedding IF statements.   

e.g. IF (<condition>, <result-if-true>, IF (<condition>, <result-if-true>, IF (<condition>, <result-if-true>, <result-if-false>)))

Use Conditional Statements in Formulas | Revit | Autodesk Knowledge Network

Revit Formulas for "everyday" usage - Revit Forum

[LXU_MPS]

It should be:

if(parameter1, 1=1, 1=0)

it works in 2023 version