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How do you create a path of travel from the second floor of a building to an exit on the first floor?
Solved! Go to Solution.
How do you create a path of travel from the second floor of a building to an exit on the first floor?
Solved! Go to Solution.
POT? You can't. Series of Model Lines would work though.
I simply use a line based detail family and draw them on Egress plans. Then create a schedule and group by mark to sum all segments of each path. Add a formula in the schedule so that when a stair box is checked for a segment, the actual length is calculated using the sqrt(rise^2 + run^2).
You can create railing as travel path. It will follow the stair profile and you are able to calculate the railing length.
Thanks, This will work. I was hoping I could do a direct route but the best I could do was get to the bottom of a stair.
Sorry for the late post but I believe that this could be accomplished with Revit's POT lines by going over a stair downward to the last step. Then do a new exit path from that point on the level below to the exit door. Set the ID for both paths to the same and add a common distance parameter to property lines. Manually note the length of the path on the 2nd story and put that distance into the common path parameter of that line. Then, in the exit path schedule sort by id and by level and uncheck itemize every instance. Set the length to total the lengths. Add a footer for the mark and choose total. So each group of lines with the same ID will have a total. The same process could be used on a single level to keep up with common paths. I used the detail line method also and that works well but this is a workaround for the new exit path limitations.
Thanks! Can anyone explain how to add the formula to the schedule? I'm not sure how the formula will know the rise/run of my stairs...
You need to enter the rise manually.
L parameter is the horizontal run
H parameter is the vertical rise
Stair tick box parameter, tick for stair, untick if not stair.
formula: if (Stair, Travel Distance = sqrt(L ^ 2 + H ^ 2), L)