How to Create Line based on Angle

[Anonymous]

I have element line location in Revit code (first line).

Then i need to add second line. 

The second line start point is any point on the line which is 90 degrees from the first line on X/Y Axis.

I cant get method to create second line based on angle.

Below is the example of the line i need.

I have been playing around with method CreateTransformed, CreateRotationAtPoint and CrossProduct but i still don't get the result i want.

Thanks.

[aignatovich · Accepted solution]

Hi! It is simple, just get a) line direction b) line sketch plane normal

Then normal.CrossProduct(direction) should be your second line direction or, may be, you need -1*normal.CrossProduct(direction)

Take any point on first line, for example, pt1 = fistLine.Evaluate(0.5, true), pt2 = pt1 + length * direction, then create the second line Line.CreateBound(pt1, pt2), then create model curve on the first line sketch plane, base on this second line

[Anonymous]

Thanks a lot Ignatovich. 

Here is my code based on your solution:

Line line1 = Line.CreateBound(XYZ.Zero, new XYZ(10, 10, 10));
XYZ pntCenter = line1.Evaluate(0.5, true);
XYZ normal = line1.Direction.Normalize();
XYZ dir = new XYZ(0, 0, 1);
XYZ cross = normal.CrossProduct(dir);
XYZ pntEnd = pntCenter + cross.Multiply(10);
Line line2 = Line.CreateBound(pntCenter, pntEnd);
Debug.Print("line1: " + line1.Direction.ToString());
Debug.Print("line2: " + line2.Direction.ToString());
Debug.Print("line1: Start " + line1.GetEndPoint(0).ToString() + " End " + line1.GetEndPoint(1).ToString());
Debug.Print("line2: Start " + line2.GetEndPoint(0).ToString() + " End " + line2.GetEndPoint(1).ToString());

[strsuraj]

Hi, @aignatovich how about creating a reference plane at a particular angle say 33 degrees. Do we have a direct method, where we can pass desired angle as an argument.

[joldman473]

Hi  @aignatovich,

Can you please show me how to get the  line sketch plane normal:

when I create it a plane by a normal ( my line direction) and an origin line origin.

The cross product plane.Normal(line.Direction) Will be equal to (0,0,0) because the two vectors have the same direction.

Thanks in advance.

[aignatovich]

sketchPlane.GetPlane().Normal