Generate 3D View Programmatically

[Anonymous]

Hi,

if i select imperial or metric template there is no 3DView listed in view by default(Revit 2015), so i want to generate 3DView programmatically,

how to achieve it.

Thanks in advance,

Regards

Kailash

[jeremytammik]

Dear Kailash,

http://thebuildingcoder.typepad.com/blog/about-the-author.html#5.37

Certainly you could have found this yourself?

Cheers,

Jeremy

[Revitalizer · Accepted solution]

Hi,

if you want to create default {3D}, you can use:

RevitCommandId commandId = RevitCommandId.LookupPostableCommandId(PostableCommand.Default3DView);

if (commandData.Application.CanPostCommand(commandId))
{
    commandData.Application.PostCommand(commandId);
}

Revitalizer

[Anonymous]

Thank you Jeremy sir,

Below is the working code which you have already mentioned in Exporting Image and Setting a Default 3D View Orientation

i picked up this one

                     var direction = new XYZ(-1, 1, -1);
                        var collector = new FilteredElementCollector(Doc);
                        var viewFamilyType = collector.OfClass(typeof(ViewFamilyType)).Cast<ViewFamilyType>()
                          .FirstOrDefault(x => x.ViewFamily == ViewFamily.ThreeDimensional);

                        using (Transaction ttNew = new Transaction(Doc, "abc"))
                        {
                            ttNew.Start();
                            var view3D = View3D.CreateIsometric(
                                              Doc, viewFamilyType.Id);

                            view3D.SetOrientation(new ViewOrientation3D(
                              direction, new XYZ(0, 1, 1), new XYZ(0, 1, -1)));
                            ttNew.Commit();

                        }

Regards

Kailash

[Anonymous]

Thank you Revitalizer,

your posted code is also working, just i placed it in a proper location in my project.and done.

Regards

Kailash

[BIM_S_S]

it work when i open one document only

not working with multiple documents

[Revitalizer]

Hi,

yes, of course, it works with the active document.

The function simulates the user clicking the related button, as all the postable commands do.

Works as exspected, I would say.

Revitalizer

[pccheung]

Dear Revitalizer,

I have lines of code of about TaskDialog.Show() after the postable command. But i don't know why the taskdialog is executed before the postable command, what mistake did i make?

Moreover, I have create the default {3D} view with the postable command, how should I make the {3D} view active and set a section box on it? 

I found that the postable command