How to obtain the angle between two vector3d? The angle 's range should be 0-2PI

How to obtain the angle between two vector3d? The angle 's range should be 0-2PI

Anonymous
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Message 1 of 15

How to obtain the angle between two vector3d? The angle 's range should be 0-2PI

Anonymous
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Hello,I define a vextor via two points(ptStart and ptDirection).And now I want to get the angle between my vector3d and the X Axis.Here is my code:

Dim Ang As Double = ptStart.GetVectorTo(ptDirection).GetAngleTo(Vector3d.XAxis)

But the range is 0-PI.Smiley SadHow can I change it to 0-2PI?

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Message 2 of 15

Marat.Mirgaleev
Alumni
Alumni

Hi,

 

   I see there is another version of this method:

 

      Vector3d.GetAngleTo Method (Vector3d, Vector3d)

      Returns the angle between this vector and the vector vector in the range [0, 2 x Pi]. 

 

   Please, find its description in the Managed Class Reference Guide (\ObjectARX 2012\docs\arxmgd.chm).



Marat Mirgaleev
Developer Technical Services
Autodesk Developer Network
Message 3 of 15

Anonymous
Not applicable

Hi! Try this.

 

double Ang = ptStart.GetVectorTo(ptDirection).GetAngleTo(Vector3d.XAxis, Vector3d.ZAxis.Negate());

 

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Message 4 of 15

Anonymous
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Nice code.haha.

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Message 5 of 15

Anonymous
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hi marat

 

although i do not want to spoil the party, i desperately fail to obtain any angles above the 0-pi interval. i admit i still use autocad 2011, however, the documentation for the .getangleto(vec; vecref) appears as you state.

 

considering the problem, i could do myself with some clarification as to how it's supposed to work:

 

starting with a vector3d, i look for the angle to another vector3d. to keep things simple, let's say they both originate in the same point and 'point away' from it in separate directions. why is there an optional reference-vector3d? if it's only to expand the interval from 0-pi to 0-2*pi, then an optional boolean would have been satisfactory.

 

many thanks, felix

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Message 6 of 15

Anonymous
Not applicable

yes of course, as soon as i posted it...

 

to whom it may concern

 

the additional vecref can be used to define [or fixate] that one dimension of the three (in 3d) that leaves the other two to span the plane in which the angle is measured. in turn it means that the option without the vecref leaves it completely to the two original vectors, i.e. the calling one and the parameter one, to define a plane and the angle within, which also explains why then with the information given it is not possible to give angles above pi, because 'they technically then do not exist'.

 

hope you enjoyed the show

 

felix

 

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Message 7 of 15

5thSth
Advocate
Advocate

hello. Sorry for ressurecting a thread, but I have an issue using the "getAngle".

the problem is the angle I'm getting is nowhere in the PI range

 

all the "input numbers" turn out as expected.

 

here's my code:

                using (Transaction tr = db.TransactionManager.StartTransaction())
                {
                    ObjectId id = res.ObjectId;
                    Point3d picked = res.PickedPoint;
                    var pline = tr.GetObject(id, OpenMode.ForRead) as Polyline;

                    Point3d onPlinePt = pline.GetClosestPointTo(picked, ed.GetCurrentView().ViewDirection, false);
                    Line3d perpLine = new Line3d(picked, onPlinePt);

                    Vector3d xAxis = new Vector3d(1,0,0);
                    Vector3d perpVector = onPlinePt-picked;

                    double myAngleRad = perpVector.GetAngleTo(Vector3d.XAxis, Vector3d.ZAxis.Negate());
                    double myAngle = myAngleRad * 180 / Math.PI;

}

and here's the result:

angles.jpg

 

 

any ideas what I'm doing wrong?

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Message 8 of 15

_gile
Consultant
Consultant

Hi,

 

The angle you get is in the 0 2pi range.

1.0094597E-188 (scientific notation) is just very closed to 0.0.



Gilles Chanteau
Programmation AutoCAD LISP/.NET
GileCAD
GitHub

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Message 9 of 15

5thSth
Advocate
Advocate

true, it was por choice of expression. 
my question stands, since I've been getting numbers 10e-188 no matter if I chose vertical, horizontal, or @ 45 deg objects

 

4 example, this is the result for a completely horizontalline - vector (1,0,0). 

the angle to Y axis should be 90deg or PI/2 (1,57)

instead, I get this results...

 

angle.jpg

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Message 10 of 15

_gile
Consultant
Consultant

5thSth a écrit :

4 example, this is the result for a completely horizontalline - vector (1,0,0). 

the angle to Y axis should be 90deg or PI/2 (1,57)



 

 

No, internally (and programmatically) AutoCAD always measures angles in radians, CCW and starting from East.

If you have different settings (e.g. ANGDIR / ANGBASE), you have to make some calculus to convert the angle or use the Converter.AngleToString() method.

 

try:

AngleToString(perpVector.GetAngleTo(Vector3d.XAxis, Vector3d.ZAxis));

 



Gilles Chanteau
Programmation AutoCAD LISP/.NET
GileCAD
GitHub

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Message 11 of 15

5thSth
Advocate
Advocate

Ive tried it, but "angleToString" method:

 

                    var newAngle = Autodesk.AutoCAD.Runtime.Converter.AngleToString(Vector3d.XAxis.GetAngleTo(Vector3d.YAxis,Vector3d.ZAxis));

                    Application.ShowAlertDialog("Angle between X and Y axis is:" + newAngle);

and result angle for X and Y axis turns out to be "0" 😞

and if I try only to .GetAngleTo(Vector3d.Yaxis)  without Z ... : 314 (which is more of a "Rad" result.

-will keep experimenting; ty

 

 

 

but I'd still like to know what the problem was with other method ;

its not a "rad/angle" conversion problem. I know all about rads, and the results Im getting are nowhere near to expected rad or deg results.

to make the problem more apparent, I've rewritten the code to print the

angle to X and Y axis... which is "90 deg" or "PI/2" in rads which is equal to "1,57"

angle to X and X axis... which is "0,00 deg" or "0,00" in rads which equals to "0,00"

 

                    double      angleResult  = new double();
                    double      angleResult2 = new double();
                    angleResult  = Vector3d.XAxis.GetAngleTo(Vector3d.YAxis);
                    angleResult2 = Vector3d.XAxis.GetAngleTo(Vector3d.XAxis);

                    Application.ShowAlertDialog("axisX vector:" + Vector3d.XAxis.ToString() + 
                                                "\naxisY vector:" + Vector3d.YAxis.ToString() +
                                                "\nAngle axisX to axisY: " + angleResult.ToString()+
                                                "\nAngle axisX to axisX" + angleResult2.ToString());

error.jpg

 

you can tell something is really wrong simply by looking at it... since angle1 and angle2 results turn out to be the same number!!! (-2,4785E +215)

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Message 12 of 15

_gile
Consultant
Consultant

Ok,

 

It seems you really have a problem with your AutoCAD (try to repar or re-install it).

 

By my side, I got correct results:

 

angle.png



Gilles Chanteau
Programmation AutoCAD LISP/.NET
GileCAD
GitHub

Message 13 of 15

5thSth
Advocate
Advocate

wow! 
Thank you for going through the trouble of testing it.

😞

 

will try to run code on desktop.

 

could be AMD cpu...

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Message 14 of 15

5thSth
Advocate
Advocate

on my desktop I get correct result.

 

but I tried to find where the bug is on laptop...

 

and when I run the dll directly from autocad, it gives correct result.

 

however, if I try to "debug" through visual studio, I get the above mentioned "error" results

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Message 15 of 15

5thSth
Advocate
Advocate

It appears the problem was my windows. I was using windows 10 -Technical Preview

I upgraded to win 10, and the problem is gone (same visual studio and Acad and it works)

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