How to enter the exact number of faces for the mesh to subdivide with?

[Silverland]

Is there any way in Maya I can subdivide without using subdivide width and hight option, but to enter the exact number of faces I want to see? I have exported the landscape mesh OBJ from the World Machine that has  16.769025 millions of faces. And let's say I want to recreate exact same mesh (not close version but exact same) 1) by using Texture deformer and 2)by using Arnold displacement and high map from the World machine. In the first case I need to guess how much it will be by entering some values in the "Subdivisions Width and Height" section and in the second case I need to change "Arnold Iteration" parameters. And I don't know the math behind each one so I don't know how many iterations or subdiv. With and Height I need to get 16.769025? So is there any options to enter precise values in both cases? Or if no what is the math numbers I need? 

[Christoph_Schaedl]

devide by four... until you reach a decent low count...

but your highres isnt a power of two mesh... its impossible to create that exact count with a subD... 

if you start with one face... you get 4 after one subD and 16 after the second...

but you dont need the exact polycount if you use displacement maps... just more to get it clean...

[Silverland]

So as I guessed out I have to play with it to get not the exact but similar look of the landscape and it's no way to enter the exact number of faces or if it's impossible to enter the exact number of faces then to enter close number of faces. The only way is to use" subdiv width and high" and play with it. OK. Thank you.

[Christoph_Schaedl]

the info for the look is in the displacement map...

if you have more poly it will be only as good as your dispmap is...

if the displacement map does have a 4k resolution it will provide around 16 mio pixel... those are 16mio hight infos...

if you have more than 16 mio poly it will be fine...