Wrong result of Rectangle.Intersect Method (DrawingView Boundaries overlap)

[Maxim-CADman77]

(this thread is consequent to https://forums.autodesk.com/t5/inventor-ilogic-and-vb-net-forum/auto-detect-view-overlap-on-idw/td-p...)

Recently I've heard about a Rectangle struct with Intersect Method (https://learn.microsoft.com/en-us/dotnet/api/system.drawing.rectangle.intersect?view=net-7.0)

With that knowledge I tried to find Rectangle resulting as overlap of two drawing view boundaries at Sheet #4 of "Inkjet Printer Prototype.idw" (a part of samples kit Inkjet_Printer_Prototype.zip for Inventor 2019 available at https://www.autodesk.com/support/technical/article/caas/tsarticles/ts/3gnm93P9sPAWE6vndk7fjq.html).

I've used this iLogic code:

Option Explicit On

AddReference "System.Drawing.dll"
Imports System.Drawing

Class DrawingViewOverlap

Dim oSheet4 As Sheet

Sub Main

Dim IsIntersecting As Boolean = 0
oSheet4 = ThisDoc.Document.Sheets(4)

Dim InitDrwViews(4-1) As DrawingView

Dim x As Integer = 0
For each oDV in oSheet4.DrawingViews
	If oDV.ViewType <> DrawingViewTypeEnum.kDraftDrawingViewType
		InitDrwViews(x) = oDV
		x +=1
	End If
Next

For i = 0 to InitDrwViews.Length - 2

	For j = i + 1 to InitDrwViews.Length - 1
		Dim oDV1 As DrawingView = InitDrwViews(i)
		Dim oDV2 As DrawingView = InitDrwViews(j)
		logger.info(oDV1.Label.Text & " -vs- " & oDV2.Label.Text)
		Dim oRect1 As New Rectangle(oDV1.Left, oDV1.Top, oDV1.Width, oDV1.Height)
		Dim oRect2 As New Rectangle(oDV2.Left, oDV2.Top, oDV2.Width, oDV2.Height)

		If TwoRectsOverlap(oRect1, oRect2) Then
			IsIntersecting = 1
			logger.info("   Intersection is found !!!")
	EXIT FOR
		End If
	Next
	If IsIntersecting Then EXIT FOR
Next

End Sub


Function TwoRectsOverlap(oRect1 As Rectangle, oRect2 As Rectangle) As Boolean
    Dim oRegion As New Region(oRect1)
	Dim oIntersect As Rectangle = Rectangle.Intersect(oRect1, oRect2)

	If Not oIntersect.IsEmpty
		DrawRect(oRect1)
		DrawRect(oRect2)
		DrawRect(oIntersect)
	End If

	Return If(oIntersect.IsEmpty, False, True)

End Function

As a result I've got somewhat close but not exactly what was expected (see Height of the Red Rectangle):

 

I'd like to know if there any mistake in my code or it is some issue on the Autodesk/Microsoft's side?

PS:
I'm using Inventor 2023.2.1.