Hi all,
I'm working through a problem and wanted to check I hadn't missed something obvious within the API.
When working with the built-in tools manually, you are occasionally presented with a "direction" arrow within the UI:
These are client graphics I believe and I have found the following article useful:
But I have an issue and that is that I need to create a version of the arrow that can be flipped about a selected axis.
Is there something I am missing within the API that can do this for me or is it a manual task of creating/recreating the transient geometry as required?
here is a c# method I have cobbled together that takes several inputs I thought may be needed:
public class ClientGFX
{
private static readonly ILog log = LogManager.GetLogger(typeof(Parameters));
public static void ClientGraphics3DPrimitives(string clientGraphicsCollectionId, Application InventorApp,
PartComponentDefinition compDef, Point origin, Point end, Line centreline, UnitVector arrowDirection)
{
try
{
Document oDoc = InventorApp.ActiveDocument;
// Set a reference to component definition of the active document.
// This assumes that a part or assembly document is active
PartComponentDefinition oCompDef = compDef;
// Check to see if the test graphics data object already exists.
// If it does clean up by removing all associated of the client
// graphics from the document. If it doesn't create it
ClientGraphics oClientGraphics = null;
try
{
oClientGraphics = oCompDef.ClientGraphicsCollection[clientGraphicsCollectionId];
}
catch (Exception ex)
{
// An existing client graphics object was successfully
// obtained so clean up
oClientGraphics.Delete();
// Update the display to see the results
InventorApp.ActiveView.Update();
log.Debug(ex.Message, ex);
}
finally
{
TransientGeometry oTransGeom = InventorApp.TransientGeometry;
// Create the ClientGraphics object.
if (oClientGraphics == null)
{
oClientGraphics = oCompDef.ClientGraphicsCollection.Add(clientGraphicsCollectionId);
}
// Create a new graphics node within the client graphics objects
GraphicsNode oSurfacesNode = oClientGraphics.AddNode(1);
TransientBRep oTransientBRep = InventorApp.TransientBRep;
// Create a point representing the center of the bottom of
// the cone
Point coneBottom = origin;
//Point coneBottom = InventorApp.TransientGeometry.CreatePoint(0, 0, 0);
// Create a point representing the tip of the cone
//Point oTop = end;
Point coneTop = InventorApp.TransientGeometry.CreatePoint(0, 10, 0);
// Create a point representing the base of the cylinder
Point cylinderBottom = InventorApp.TransientGeometry.CreatePoint(0, -40, 0);
//sort out the direction we need to point.
Matrix conePos = InventorApp.TransientGeometry.CreateMatrix();
Vector conePosVector = InventorApp.TransientGeometry.CreateVector(arrowDirection.X, arrowDirection.Y, arrowDirection.Z);
conePos.SetTranslation(conePosVector);
conePos.SetToRotateTo(coneTop.VectorTo(coneBottom), conePosVector);
//move the necessary points
coneTop.TransformBy(conePos);
cylinderBottom.TransformBy(conePos);
// Create a transient cone body
//SurfaceBody oBody = oTransientBRep.CreateSolidCylinderCone(oBottom, oTop, 5, 5, 0);
SurfaceBody oBody = oTransientBRep.CreateSolidCylinderCone(coneBottom, coneTop, 5, 5, 0);
// Reset the top point indicating the center of the top of
// the cylinder
//oTop = InventorApp.TransientGeometry.CreatePoint(0, -40, 0);
coneTop = InventorApp.TransientGeometry.CreatePoint(0, -40, 0);
// Create a transient cylinder body
//SurfaceBody oCylBody = oTransientBRep.CreateSolidCylinderCone(oBottom, oTop, 2.5, 2.5, 2.5);
SurfaceBody oCylBody = oTransientBRep.CreateSolidCylinderCone(coneBottom, cylinderBottom, 2.5, 2.5, 2.5);
// Union the cone and cylinder bodies
oTransientBRep.DoBoolean(oBody, oCylBody, BooleanTypeEnum.kBooleanTypeUnion);
// Create client graphics based on the transient body
SurfaceGraphics oSurfaceGraphics = oSurfacesNode.AddSurfaceGraphics(oBody);
// Update the view to see the resulting curves
InventorApp.ActiveView.Update();
}
}
catch (Exception ex)
{
log.Error(ex.Message, ex);
}
}
}
I think perhaps I have misunderstood the Matrix translation required in this instance.
Any pointers will be gratefully received!
Thanks,
Alex.
![2017-11-08 09_18_11-Autodesk Inventor Professional 2017 - [DBE200040.IPT].png](https://forums.autodesk.com/t5/image/serverpage/image-id/423269iAD9C6C6A9526DF92/image-size/large?v=v2&px=999 "2017-11-08 09_18_11-Autodesk Inventor Professional 2017 - [DBE200040.IPT].png")
