SketchLine Object causes AddByProjectingEntity to throw exception.

[Anonymous]

This code worked fine in Inventor 2008 however when i call this function is 2010 an Invalid Args Exception is thrown when a SketchLine is passed in. Anyone know whats going on here? asmsketch is a PlanarSketch object.

{code}
for (int j = 1; j <= asmsketch.SketchLines.Count; j++)
{
cutSketchProxy.AddByProjectingEntity(asmsketch.SketchLines);
}
{code}

Edited by: shouston on Oct 28, 2009 8:55 PM Edited by: shouston on Oct 29, 2009 1:13 PM

[Anonymous]

Is asmsketch a sketch in the assembly or a sketch within a part?

Sanjay-

[Anonymous]

asmsketch is a sketch in the assembly.

[Anonymous]

I was able to verify that there is indeed an issue projecting assembly
sketch entities using the API. I've filed this with a high priority in our
system. Unfortunately, I don't know of a workaround. Sorry.

Thanks for reporting this.

Sanjay-

[chuck_b]

Sanjay,

Any update on this topic? We will not be able to upgrade to 2010 until issue is resolved. A part can project it's sketch geometry two another part's sketch in an assembly only if it is one level deep. Deeper than that it doesn't work in 2010. No issues with Inventor 2008 when projecting sub assembly parts geometry to other sub assembly parts. Our findings have nothing to do with assembly sketches. We are using part sketches only. I can provide sample vba code and Inventor files to help identify problem.

Thanks,


Chuck

Edited by: Chuck_B on Nov 16, 2009 9:35 PM

[Anonymous]

We did have this issue of not being able to project entities if they are
more than one level deep. But I thought the issue was resolved in Inventor
2010. Could you please provide data files and VBA code to reproduce?

thanks,
Sanjay-

[chuck_b]

Should be able to open proj1.iam and run code. We tested this also one level deep and it worked on 64bit machine Inventor 2010 sp1 but not sub levels. Works good with 2008 as I mentioned. Sorry about the messy code. I had to quickly make something simple

Thanks for any help you can provide.

Chuck

{code}
Dim a As AssemblyDocument
Dim occ1 As ComponentOccurrence
Dim occ2 As ComponentOccurrence

Set a = ThisApplication.ActiveDocument
Set occ1 = a.ComponentDefinition.Occurrences(2).SubOccurrences(1)
Set occ2 = a.ComponentDefinition.Occurrences(1).SubOccurrences(2)

Dim odoc1 As PartDocument, odoc2 As PartDocument

Dim oSkToProjectOn As PlanarSketch

Dim oSkToProjectOnProxy As PlanarSketchProxy

Set odoc1 = occ1.Definition.Document

Set odoc2 = occ2.Definition.Document



Dim oCirc As SketchCircle, oCircProxy As SketchCircleProxy

Set oCirc = odoc2.ComponentDefinition.Sketches("Sketch2").SketchCircles(1)

occ2.CreateGeometryProxy oCirc, oCircProxy



Set oSkToProjectOn = odoc1.ComponentDefinition.Sketches("Sketch2")

occ1.CreateGeometryProxy oSkToProjectOn, oSkToProjectOnProxy





oSkToProjectOnProxy.AddByProjectingEntity oCircProxy

{code}

Edited by: Chuck_B on Nov 17, 2009 1:20 PM Edited by: Chuck_B on Nov 17, 2009 1:29 PM

[Anonymous]

Yes, I'm afraid I'm able to reproduce the issue. I've added this workflow to
the previous report and given it a even higher priority. Please use the ID
1271172 for tracking purposes.

Thanks for reporting this.

Sanjay-

[chuck_b]

Thanks Sanjay,

Any guestimate about how long this could take to fix? I know it is almost impossible to determine. 2-4 months or even less if it is a high priority item?

Thanks,

Chuck

[Anonymous]

Sorry, I'm unable to comment on the timeframe of a fix.

Sanjay-

[chuck_b]

Is there a way to track this issue ID 1271172 ? Or is this to be used when referencing purposes only?

Chuck

[Anonymous]

No, there isn't a way to track it. You can post the id on the newsgroup, and
one of us here at Autodesk can look it up for you.

Sanjay-

[ludesroc]

Any developpement on this post?

Regards,
Ludesroc

[ludesroc]

Any developpement on this post?

Regards,
Ludesroc

[Anonymous]

This issue should be fixed in the just released Inventor 2011. A fix is also
being considered for service packs of previous versions of Inventor, but no
final word on that yet.

Sanjay-

[ludesroc]

Ok thanks Sanjay.

Ludesroc