Does anyone know a trig function to solve for "X"?

Does anyone know a trig function to solve for "X"?

chris
Advisor Advisor
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Message 1 of 8

Does anyone know a trig function to solve for "X"?

chris
Advisor
Advisor

I'm trying to solve for "X", but I need to do it based on 3 knowns: (LOD, SOD and Radius)

I'd like to see how to write this in both Parameters as well as how to write it in iLogic

 

or

 

how to solve for "Y", as I have a formula to solve chord length, but that requires knowing the angle of "Y"

 

chris_0-1714226744977.png

chris_0-1714227669636.png

 

 

 

 

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497 Views
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Replies (7)
Message 2 of 8

ServiceRRVWQ
Participant
Participant

Hi chris, try this.

ServiceRRVWQ_19-1714232535529.pngServiceRRVWQ_20-1714232576572.png

 

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Message 3 of 8

chris
Advisor
Advisor

I was able to figure it out with a couple sketches and some triangles, it now looks like this:

chris_0-1714236823268.png

chris_1-1714237030784.png

 

 

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Message 4 of 8

chris
Advisor
Advisor

Here's the pay off from those equations

 

Message 5 of 8

mat_hijs
Collaborator
Collaborator

You have 2 sides of a right triangle, you can use a²+b²=c² to get the third and then x would be R minus the third side.

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Message 6 of 8

Curtis_Waguespack
Consultant
Consultant

@chris 

I'm not sure if this will help for your goal, but recall that we can right click on a pattern element and choose Independent, and then go to Assemble tab > Productivity panel > and use the Save and Replace tool to make a new part.

 

Curtis_Waguespack_0-1714397010170.png

 

Curtis_Waguespack_1-1714397128354.png

 

EESignature

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Message 7 of 8

chris
Advisor
Advisor

@Curtis_Waguespack What exactly is changing it to independent doing? If I updated the pattern feature with it also affect the parts I set to independent and save and replaced?

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Message 8 of 8

chris
Advisor
Advisor

@mat_hijs Thanks, I got those figured out yesterday and I added a few more equations for others to use, it's in a post called:      Here are some Parameter equations for a Right Triangles... have fun

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