API Call woodwork application Python (WW4I)

[cavallerin]

How can I create an instance for woodwork 4 inventor addin inside a python script?

import win32com.client as wc

# istanzio l'applicazione di inventor
try:
    inv = wc.GetActiveObject('Inventor.Application')
    ww = inv.woodworkApplication

except:
    inv = wc.Dispatch('Inventor.Application')
    inv.Visible = True

[Michael.Navara · Accepted solution]

Hi @cavallerin 

Woodwork is an add-in for Inventor, not built-in component.

All you can try is to get its Automation property and look, if it provides any API functions. Unfortunately this property usually returns NULL or some unknown object.

[cavallerin]

Ok thx a lot it worked, but to get the WW4I object I use this calling:

ww = inv.ApplicationAddIns.Item(49).Automation

where 49 is the progressive number of the addin in my system.

Maybe I'm wrong, but does Inventor use internal Id(s) to identify this objects? Is there a way to get it?

[Michael.Navara]

If number 49 works now, you can obtain its ClientId and use it instead of this index. This Client id is persistent for whole lifecycle of the addin.

ww4iClientId=inv.ApplicationAddins.Item(49).ClientId

ww = inv.ApplicationAddIns.ItemById(ww4iClientId).Automation
# Or
ww = inv.ApplicationAddIns.ItemById('WW4I-CLIENTID-GUID-HERE').Automation

Sorry I'm not familiar with python. Excuse me if there are some syntax error.

[cavallerin]

{FEF38B5F-CACF-4647-8EE5-1F642F03C610}

got it!

But what do you mean by "This Client id is persistent for whole lifecycle of the addin." ?

A colleague of mine can set the same UUID?

[Michael.Navara]

It means this ClientId is the same for all versions of WW. It should be stable for future versions.