Hi @Anonymous
It is not the increment of the load that is important. It is the change of stiffness and/or the displacement change that is calculated more accurately when you have more increments. As parts deflect, the load carrying ability changes, or contact changes where the load is transferred, and so on.
I do not know what your model is, but how can it have 1.84 units of displacement with 0 load? Something seems wrong to me.
John Holtz, P.E. Global Product Support
Autodesk, Inc. If not provided already, be sure to indicate the version of Inventor Nastran you are using!"The knowledge you seek is at knowledge.autodesk.com" - Confucius 😉