Vertical Dimension

[Anonymous]

To begin this sketch I need Vertical Dimension between two parallel lines (indicated in the diagram). Only Horizontal Dimension is given. Is there any other way to find out Vertical Dimension between two parallel lines?

I found by using coordinate geometry.

d = .75cos30

[mdavis22569]

are you looking to do this?

[Anonymous]

Yes I am looking that dimension. But this  dimension is not given only through the calculation you can get. I wish to know is there any way in Inventor to know this dimension.

[JDMather]

All of the needed dimensions are given.

You should (almost) never need trigonometry in Inventor - use geometry (which solves the trig).

Use geometry constraints, use geometry constraints, use geometry constraints.

Did I mention, use geometry constraints? 

You are missing Parallel and Perpendicular constraints.

You should never ever use Fixed constraint.

Keep in mind that that drawing is ancient - long before there was CAD.

(I did it back in the last century on the drawing board when I was in school.

The dimension arrows are not exactly correct (should be perpendicular to the parallel faces).

Actually, that looks like a rip-off of the original art.  The dimension isn't drawn correctly.

[mdavis22569]

They gave you the .75 dimension, so you can model it to that thickness. 

Continue modeling it to the provided dim's and you should get everything you need to make it to what they are showing.

The way you questioned it ...you made it seem like yo uwere asking to to get that type of a dim...

and you programmed in the .65 yourself manually ...

 

[Anonymous]

How get needed dimension "d" to draw the sketch.

[mcgyvr]

You don't need that dimension as already stated.. (he is asking about the red line not the .75 dimension thats already there)

But even looking at the drawing the dimension is .750-.125=.625

But again you don't need it..

You model the part complete WITHOUT THE FILLETS first.

So use the .750 dimension thats already given..

Then when done with that go back and add all the .125R fillets/rounds.

[mdavis22569]

edited to add screen cast ..

change the .65 to .75, add the .125 r fillet and you'll get the dim's you're looking for. 

[Anonymous]

Book suggest me to use Fixed constraint. That is why I used it.

[mdavis22569]

ok ...but that has nothing to do with the thickness.. just keeps it located at that point with the origin.   

[JDMather]

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@Anonymous wrote:

Book suggest me to use Fixed constraint. That is why I used it.

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No, it does not say use Fixed Constraint.  It says to fix your corner to 0,0,0.  That means add a Coincident constraint between that point and the projected origin (which Inventor will do for you automagically if you are sketching correctly).

[Anonymous]

You should never ever use Fixed constraint.

What does it mean?

[mdavis22569]

just like it says 

Fix Corner at 0,0,0 ....  you could constraint that corner to the origin point 

you have of the values because of the plane .. so you need a horizonal and vertical to the origin.

[mcgyvr]

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@Anonymous wrote:

You should never ever use Fixed constraint.

What does it mean?

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It means do not use fixed constraint.. Use coincident instead..

Using coincident will allow the point to move in relation to the point it was constrained to if you make changes to the sketch.

If you use a fixed constraint then that point will NOT move properly.. 

[JDMather]

You could, of course, use a Fixed Constraint - but I recommend that you forget that constraint even exists.

I have seen too many beginners use it improperly and then it is impossible to break their bad modeling habits.

The only time I use fixed constraint is to test Sketch Blocks or Punch Sketches - and then I delete it once my test is over.

These two topics are way beyond what you are ready for at this time.

If you think you need a fixed constraint - ask questions.  You now know that it is almost certainly incorrect constraint to use.

[Anonymous]

I know Coincident Constraint. I know Fix point. No idea about Fixed Constraint.

[mcgyvr]

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@Anonymous wrote:

I know Coincident Constraint. I know Fix point. No idea about Fixed Constraint.

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fix is the same as fixed..

JD is saying don't use "fix" just use "coincident" to constrain that corner point to your origin center point

[JDMather]

Serenity now JD, serenity now.

OK, back to work.

These are ALL geometry constraints.

Left to right, top to bottom

Coincident, Colinear, Concentric, Fixed

Parallel, Perpendicular, Horizontal, Vertical

Tangent, Smooth (forget about this one too, at least for then next couple of years), Symmetry (mirror), Equal

They constrain (remove Degrees of Freedom (DoF) from your geometry in logical ways so that your geometry behaves in a logical manner when edited. 

[Anonymous]

I use all geometry constraints frequently. But I have no idea about Fixed Constraint.

In the above blur tools are the Fixed Constraint?

[Anonymous]

I tried to redraw the model. How to make it fully constraint without using trigonometry.