USING PARAMETERS FOR A ROCKER BOGIE HELP

USING PARAMETERS FOR A ROCKER BOGIE HELP

Anonymous
No aplicable
1.084 Vistas
8 Respuestas
Mensaje 1 de 9

USING PARAMETERS FOR A ROCKER BOGIE HELP

Anonymous
No aplicable

So I m trying to optimize a rocker bogie suspension system but I am running into a few problems using the parameters. I am having problems with my parameter "L4" it should be a Patagonian equation for a triangle length: (S1^2+(2R))^(-1) but when I try it on my calculator I get different values then the nominal. I also get the text in red. I hope this is the cause for it not being able to finish the constraints since i am fairly certain my parameters I derived are correct. I attached images of what I am trying to do and what the inventor software is showing

 

thanks, Sage Edwards

 

 

CORRECTION: found that I can define L4 as L4=H1

also the angle between the bogie arms is constrained to 90deg

 

Update: I am thinking i need to revisit my equations but if i can get an explanation for the red text that would be great

0 Me gusta
Soluciones aceptadas (1)
1.085 Vistas
8 Respuestas
Respuestas (8)
Mensaje 2 de 9

JDMather
Consultant
Consultant

It doesn't look to me like you have accounted for your units.

 

I recommend that you right out the equation on paper with the units included.


-----------------------------------------------------------------------------------------
Autodesk Inventor 2019 Certified Professional
Autodesk AutoCAD 2013 Certified Professional
Certified SolidWorks Professional


0 Me gusta
Mensaje 3 de 9

Anonymous
No aplicable

my equations are not dependent on units they are just basic trig and geometry equations. I am checking my equations on paper now but that doesn't explain the red error text. Did I type it in wrong? 

0 Me gusta
Mensaje 4 de 9

Anonymous
No aplicable

Additional question: I would like to make R (radius of wheel) to be a variable) Is this something I can do? 

0 Me gusta
Mensaje 5 de 9

JDMather
Consultant
Consultant

@Anonymous wrote:

my equations are not dependent on units .... 


R is in mm
S1 is in mm

L4 is mm

 

Inventor doesn't forget the units.

 

I am doing some experimenting, I suspect that you cannot use implied negative ^-1ul


-----------------------------------------------------------------------------------------
Autodesk Inventor 2019 Certified Professional
Autodesk AutoCAD 2013 Certified Professional
Certified SolidWorks Professional


0 Me gusta
Mensaje 6 de 9

JDMather
Consultant
Consultant

@Anonymous wrote:

my equations are not dependent on units .... 


R is in mm  You have R=100mm which you are then squaring
S1 is in mm You have S1=286.706mm which you are then squaring

L4 is mm

 

Inventor doesn't forget the units.

 

I am doing some experimenting, I suspect that you cannot use implied negative ^-1ul


-----------------------------------------------------------------------------------------
Autodesk Inventor 2019 Certified Professional
Autodesk AutoCAD 2013 Certified Professional
Certified SolidWorks Professional


Mensaje 7 de 9

Anonymous
No aplicable
ok thankyou i didnt see anything for squarroots so i just did that
0 Me gusta
Mensaje 8 de 9

Anonymous
No aplicable
Solución aceptada

Dear sedwar22,

 

Putting a quantity to the negative first power divides one by the quantity.  x^-1 = 1/x

 

What you would want to do to take the square root in the parameters is use the sqrt() function.

 

You might also want to re-enter your argument and put parenthesis around the powers. sqrt((S1^2ul)-((2 ul*R)^2))

 

0 Me gusta
Mensaje 9 de 9

Anonymous
No aplicable

whoops i meant to have it to the power of 1/2 lol but yes i have tried putting the powers in () but thanks for the sqrt function i didnt know it was used here since i didn't see it on the list of commands i could use. but thanks i will give it a go

0 Me gusta