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I'm just starting to play around with some of Inventor 2014's stress analysis features and could use a little help. One thing I was having a problem with is applying a force where I want to. I wanted to apply a force to a face but not in the center point, is there any easy way to do this? The best workaround I came up with was creating another very small face with the center where I wanted the force to be applied. The next thing I'm wondering is if there is a way to test what force would cause the part to break. So far I've just been inceasing the force on each simulation until I find a force that's safety factor is close to 1
(attach your file here if you can't figure it out)
Inventor FEA does not test if a part will "break".
Safety Factor below one does not mean the part fractures - it simply means the deformation has crossed from elastic to plastic (permanent).
----------------------------------------------------------------------------------------- Autodesk Inventor 2019 Certified Professional Autodesk AutoCAD 2013 Certified Professional Certified SolidWorks Professional
That makes since but is there a way to find the force that causes the permanent deformation or do I have to run several simulations until I zero in on a force that is close?
The high stress area could localized to a very small area or location that is of no real concern in the function of the part.
----------------------------------------------------------------------------------------- Autodesk Inventor 2019 Certified Professional Autodesk AutoCAD 2013 Certified Professional Certified SolidWorks Professional
An assembly file (*.iam) is only a list of hyperlinks to the part files (*.ipt) and a record of assembly constraints (and a bit more).
You must include the part files.
----------------------------------------------------------------------------------------- Autodesk Inventor 2019 Certified Professional Autodesk AutoCAD 2013 Certified Professional Certified SolidWorks Professional
If it's a single force load, you should be able to do this. (Note: the resulting minimum SF value must be below 15 for this to work. If it's not, increase the load value until it is.) Once the minimum SF is below 15, multiply that load magnitude by the resulting minimum safety factor. Use that multiplied value as the load input and it should bring the minimum SF to exactly 1.
In your case, you'd multiply the 2500 lbforce * 0.89 (attached). Use the 2225 lbforce as input.
