Sketch blocks constraining
- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Report
Hi everyone,
I make extensive use of blocks in sketches, but I find it difficult to understand the logic of Inventor 2013 in this matter.
Example:
I open a sketch, draw a two point rectangle, give two (aligned) dimensions to its sides, assign two dimensions of a corner with respect to the origin. Everything turns blue and I'm happy.
Now I press F8 and remove the horizontal constraint which has been put automatically, next I delete the origin. I have now three degrees of freedom, as it must be for a rigid shape in a plane.
My rectangle behaves in the 2D plane of the sketch like an unconstrained part in the 3D space of an assembly. That's exactly what I want: I turn the rectangle into a block for later use in other sketches.
But when I open the block, I find that it has FIVE degrees of freedom. What does this mean?
Firstly, the three DOF for translation and rotation shouldn't be displayed, because there's no way to remove them, because in blocks you cannnot project a coordinate system. I think blocks should have a "local" coordinate systems exactly like parts do. In fact, imagine a complicated block with lots of geometry and dimensions: you miss one dimension and you press F8 to see where it is, and the screen becomes a huge mess of red arrows. You then try to move the green lines to find a clue, but often also this doesn't help because in many cases Inventor gives priority two the translation and rotation DOF.
Secondly, and more importantly, what are the other two DOF? Going back to the rectangle, I try to add constraints: I try to put horizontality to one side. But horizontality with respect to what? But anyway, the DOF are now four. I cannot put any more constraints. I try to use the "fix" constraint to everything. It works, the rectangle is blue, even if Inventor says there are 2 DOF.
Can someone explain me where I'm wrong?