Solved: ilogic part insertion - Page 2

Anonymous · ‎10-19-2012

I am working on an assembly with lots of parts that are turned on and off (Component.IsActive) using ilogic, depending on which is selected. The model is for a steel door, and the parts we have constrained are all the various options for hardware, such as lock cases and door closers. All the parts are already set up in a library, but are also present in our top level assembly.

As the assembly is getting bloated with all the parts and constraints, I was wondering if it was possible to have ilogic automatically insert (and constrain) a part from a library into the active assembly, not just unsuppress a previously inserted part.

Does anyone know of a way to do this with ilogic?

Inventor 2013 SP1

Anonymous · ‎08-02-2013

Okay, First of all you are not making the hinge with ilogic......

You will use ilogic to control which hinge it is used, the quantity and the position.

Sounds like you want to make the Hinge a ipart or iassembly then your 18,22,28,30 and 34" would be members of the factory. This would take care of the number of holes in the hinge

Is the hinge a part or an assembly?

This is where i would start first

Anonymous · ‎08-02-2013

In the grand scheme of things, I need to be able to type in the size of my door, and iLogic select the appropriate hinge (2 different types) and install them in the correct location , or either the left or the right side of the door. I guess since I already have the door sizing rule working correctly, the next step is ipart right?

Anonymous · ‎08-02-2013

yes it would appear so

Anonymous · ‎08-02-2013

Okay. I have my hinge drawn. What do you recommend as my next step? I am going to guess write rules specifing that the 18 in. hinge has 3 holes and they are 6 in. apart and so on. I created it as an iPart and made like 4 more hinges, so are those "rules" already written?

Anonymous · ‎08-02-2013

Okay. I have my hinge drawn. What do you recommend as my next step? I am going to guess write rules specifing that the 18 in. hinge has 3 holes and they are 6 in. apart and so on. I created it as an iPart and made like 4 more hinges, so are those "rules" already written?

No, there are no ilogic rulesto write to specify the number of holes etc

Create your ipart factory with all the features that are required in the members for example create it with 4 holes then in each member either suppress or Compute those features in each member.

In the end you will have a number of members which correspond to each of your hinges

no ilogic required

Anonymous · ‎08-02-2013

Yup, I figured that one out 🙂 So how do I tell the program which form of the hinge should be installed when the door width is within a certain range?

-Jonathon Wood A-101

Anonymous · ‎08-02-2013

okay..........here goes

Assemble your ipart factory component into your assembly...........you will be prompted to select a member, choose one doesnt matter which right now.

Then stabalize the name in the model tree.........lets imagine you rename it to MyHinge

Then you need to decide what "logic" you are going to use to decide which hinge will be used.

I am going to make an assumption here

lets say you have 3 different hinges SMALL, MEDIUM and LARGE

and the width of the door is the deciding factor as to which hinge to use

So you would have a parameter with the door width value............lets say its named DOOR_WIDTH

There are a few ways the code to swap the hinge member out this is one way

Select Case DOOR_WIDTH

Case 20

iPart.ChangeRow("MyHinge","small")

Case 30

iPart.ChangeRow("MyHinge","medium")

Case 40

iPart.ChangeRow("MyHinge","large")

end select

Anonymous · ‎08-02-2013

What does the case number mean?

-Jonathon Wood A-101

Anonymous · ‎08-03-2013

this link will explain

http://wikihelp.autodesk.com/Inventor/enu/2013/Help/1310-Autodesk1310/1878-iLogic1878/1880-Conditio1...

"How can i use a select case statement"

Anonymous · ‎08-03-2013

Ok, I created this hinge yesterday as an ipart and placed it into an assembly. I can select all 5 sizes, but it out puts the same size each time.... what did I do wrong?

-Jonathon Wood A-101

Anonymous · ‎08-03-2013

Not a lot of information to know what is wrong.

Did your ilogic rule for changing out the members run with no errors?

Post your code

What version of Inventor are you using

Anonymous · ‎08-03-2013

Yes it ran with no errors, I am using 13. Here is my code
If Length = "18" Then
MultiValue.SetList("Space", 5.8125, "6.6875 in", 7.79166666, 8.4375, 9.875)
MultiValue.SetList("holes", "3 ul", 4)
holes = 3 ul
Else If Length = "22" Then
MultiValue.SetList("Space", "5.8125", 6.6875 in, 7.79166666, 8.4375, 9.875)
MultiValue.SetList("holes", 3 ul, "4 ul")
holes = 4 ul

Else If Length = "28" Then
MultiValue.SetList("Space", 5.8125, 6.6875 in, "7.79166666", 8.4375, 9.875)
MultiValue.SetList("holes", 3 ul, "4 ul")
holes = 4 ul
Else If Length= "30" Then
MultiValue.SetList("Space", 5.8125, 6.6875 in, 7.79166666, "8.4375", 9.875)
MultiValue.SetList("holes", 3 ul, "4 ul")
holes = 4 ul
Else If Length = "34" Then
MultiValue.SetList("Space", 5.8125, 6.6875 in, 7.79166666, 8.4375, "9.875")
MultiValue.SetList("holes", 3 ul, "4 ul")
holes = 4 ul
End If

Thank you all for all of your help!

-Jonathon Wood A-101

Anonymous · ‎08-03-2013

No part of the code you posted changes the ipart member

Anonymous · ‎08-03-2013

Oh..... How do I write that?

Anonymous · ‎08-03-2013

I gave you an example of how to do that in an earlier post

Anonymous · ‎08-03-2013

Sorry about that, I must have missed that

Is this correct?

Case 1
iPart.ChangeRow("Rolled Barrel Strap Hinge","H-316RB-18")
Case 2
iPart.ChangeRow("Rolled Barrel Strap Hinge","H-316RB-22")
Case 3
iPart.ChangeRow("Rolled Barrel Strap Hinge","H-316RB-28")
Case 4
iPart.ChangeRow("Rolled Barrel Strap Hinge","H-316RB-30")
Case 5
iPart.ChangeRow(

-Jonathon Wood A-101

Anonymous · ‎08-03-2013

almost! you need to add Select Case and End select at the end
Also after Select case add the parameter name you are using. The one that has values 1,2,3,4,5

Anonymous · ‎08-03-2013

If Length = "18" Then
MultiValue.SetList("Space", 5.8125, "6.6875 in", 7.79166666, 8.4375, 9.875)
MultiValue.SetList("holes", "3 ul", 4)
holes = 3 ul
Else If Length = "22" Then
MultiValue.SetList("Space", "5.8125", 6.6875 in, 7.79166666, 8.4375, 9.875)
MultiValue.SetList("holes", 3 ul, "4 ul")
holes = 4 ul

Else If Length = "28" Then
MultiValue.SetList("Space", 5.8125, 6.6875 in, "7.79166666", 8.4375, 9.875)
MultiValue.SetList("holes", 3 ul, "4 ul")
holes = 4 ul
Else If Length= "30" Then
MultiValue.SetList("Space", 5.8125, 6.6875 in, 7.79166666, "8.4375", 9.875)
MultiValue.SetList("holes", 3 ul, "4 ul")
holes = 4 ul
Else If Length = "34" Then
MultiValue.SetList("Space", 5.8125, 6.6875 in, 7.79166666, 8.4375, "9.875")
MultiValue.SetList("holes", 3 ul, "4 ul")
holes = 4 ul
End If
Select Case "1,2,3,4,5"
Case 1
iPart.ChangeRow("Rolled Barrel Strap Hinge","H-316RB-18")
Case 2
iPart.ChangeRow("Rolled Barrel Strap Hinge","H-316RB-22")
Case 3
iPart.ChangeRow("Rolled Barrel Strap Hinge","H-316RB-28")
Case 4
iPart.ChangeRow("Rolled Barrel Strap Hinge","H-316RB-30")
Case 5
iPart.ChangeRow("Rolled Barrel Strap Hinge","H-316RB-34")
End Select

Anonymous · ‎08-03-2013

No that will not work

I think you need this

Select Case Length
Case 18
iPart.ChangeRow("Rolled Barrel Strap Hinge","H-316RB-18")
Case 22
iPart.ChangeRow("Rolled Barrel Strap Hinge","H-316RB-22")
Case 28
iPart.ChangeRow("Rolled Barrel Strap Hinge","H-316RB-28")
Case 30
iPart.ChangeRow("Rolled Barrel Strap Hinge","H-316RB-30")
Case 34
iPart.ChangeRow("Rolled Barrel Strap Hinge","H-316RB-34")
End Select

Anonymous · ‎08-03-2013

Here is the error message I got 😕 I can taste how close this is haha

Error in rule: strap_size, in document: Rolled Barrel Strap Hinge.ipt

Object reference not set to an instance of an object.

-Jonathon Wood A-101

ilogic part insertion

ilogic part insertion

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