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First time posting on here and I am mostly a newbie with Fusion 360, so I apologize in advance if this is a silly question.
Here is my issue/scenario: I created 5 parameters in my design;
1. MyOD = 12" -- I will manually change the diameter here
2. MyThickness = MyOD-.75" -- The idea is if I change the OD of my circle the distance between my outer/inner circles will remain the same
3. MyCircum = MyOD * PI -- Gathering the circumference of my circle here
4. MyCircle = .25" -- The 'grooves' in my design will always be .25" diameter - I realize that creating a parameter for something that will always be that size is unnecessary, but just doing it for consistency right now
5. MyGrooves = round(MyCircum / .75") -- I need to spacing to be close to .75" between gooves regardless of the diameter that I select in step 1 above, so they are rounded to the nearest whole number
My process is that I create 2 circles. The first circle dimension is set to 'MyOD' and the second is set to 'MyThickness', this give me the expected result. Then, I create another circle that is coincident to the 'MyOD' line and I set it to 'MyCircle', this also gives me the expected result. This is where it gets messed up though, after creating 'My Circle' I use the trim command and split the circle in half (I suspect this is where I am messing up), and I also trim the 'MyOD' line as well, this is the profile that I want to actually circular pattern around the OD. I click on circular pattern, select my half circle that I want to pattern, type 'MyGrooves' into the quantity box, which in my example should pattern a total quantity of 50 (round(MyCircum / .75), but it will not allow it.
I realize this is likely a very simple design process for others but I been stumped on this for days now haha. There is 10 better ways of accomplishing this I am sure. Hopefully this makes sense though! The idea behind all of this is that I only have to draw it 1 time and in theory it should automatically update the total number of grooves based on the OD that I input.
Solved! Go to Solution.