Easiest way to create this polyhedron?

[atdNMH7S]

I need to sketch a six-sided polyhedron that consists of a square face on the lefthand end, and a rectangular face on the righthand end. These two faces are parallel to each other. However, no other measurements can be assumed -- one of these two faces may end up offset relative to the other in one or two dimensions, so this is not anything as simple as a truncated pyramid.

Is there an easy way to do this in Fusion 360? Intuitively I want to sketch the square and the rectangle in a 3D space, and then connect them with lines. Is this possible? Other kinds of approaches (for example, defining portions of surfaces and extruding them) seem like they would get complicated.

[davebYYPCU · Accepted solution]

2 sketches, one for the square, other for the rectangle.  

Slide for required relative position

Loft them for a connecting body.

Might help.....

[jhackney1972]

Your description and your diagram do not match.  You say a square on the left and a rectangle on the right but your picture shows a rectangle on the left and square on the right.  Maybe you just labeled them wrong.  Does the Screencast show what you want?

[atdNMH7S]

Thank you! Very much a beginner, so I hadn't gotten to Loft yet.

My next question was going to be how to create the offset plane, but then I came across Construct > Offset Plane and was able to make a simple loft of two planes. Appreciate the help.

[atdNMH7S]

Thanks for the reply. Yes, it had occurred to me that the sketch I used didn't cover all possible cases. As mentioned in the description, the square face on the left and the rectangular face on the right are parallel to each other, but nothing else can be assumed. The rectangle will probably end up offset in one or two dimensions relative to the square.

In any case, the mention of the Loft command in another post was enough to get me started. Thanks again for the response.