custom parameters

[stevehattCXSXP]

scenario - I have a part 500mm long that has 2 holes in it, if I want to increase it to 750mm I want 3 holes in it (equally spaced) and depending on rule to increase number of holes based on overall length, over 1000mm 4 holes etc etc.

Is there a way to create a custom parameter to work this out? I can do it with the same amount of holes and automatically adjust the spacing but can't get my head around increasing the number of holes based on changing the length...

[jacob.michaels]

Make a user parameter with no value that's your desired relationship between length and the number of holes. In this case (length/250mm). if length=750, the value will be 3. Use this parameter as the number value in a rectangular pattern, or pattern on path. you can play around more with this and add more granularity to this by adding floor() to the function to round the value down until you get to your next whole number.

[kandennti]

Hi @stevehattCXSXP -San.

I'm not talking about the API, am I?

An update a while ago made IF minutes available as a parameter, so you can make a conditional decision.

https://help.autodesk.com/view/fusion360/ENU/?guid=GUID-76272551-3275-46C4-AE4D-10D58B408C20 

This is a Japanese forum, so everything is in Japanese, but we all had fun sharing ideas about a modeling problem where the number of reinforcing ribs changes depending on the height of the boss.

https://forums.autodesk.com/t5/fusion-360-ri-ben-yu/ribuno-ben-shuga-ke-biansurumoderu/m-p/11936412 

[stevehattCXSXP]

Hi, I can relate to this but can only get it to give me a couple of variables. 

My scenario is to return a value to meet the following -

'length'<500,2

'length'>499<750,3

'length'>750<1000,4

else 1

(if(length<500;2;if((length>499);3;if(length>750;4;1)))) fusion accepts the expression but it doesn't work, only the first 2 arguments. 

What am I missing please, or is there another way of doing it?

[Jorge_Jaramillo]

Hi @stevehattCXSXP ,

This formula works for me:

if(length <= 500 mm; 2; if(length <= 750 mm; 3; if(length <= 1000 mm; 4; 1)))

Please note that if you want to use "number_holes" variable in a dimension that is not related to a distance, it has to be defined without unit.

Regards,

Jorge Jaramillo

Software Engineer

[kandennti]

@stevehattCXSXP -San.

Your expression "499.5" would not give the desired result, since both "length<500" and "length>499" would be valid.

It is easier to understand if the direction of the inequality sign is unified.

length < 500 mm --> 2
length < 750 mm --> 3
length < 1000 mm --> 4
more than that --> 5

the following will do what you want.

if(length < 500 mm; 2; if(length < 750 mm; 3; if(length < 1000 mm; 4; 5)))

The file is attached.

[stevehattCXSXP]

Thanks for that, makes sense. Now I need to learn how to introduce this into a pattern to drive the number of holes in a component.  This is where I am at but I can't assign the 'spacing' to the R-Pattern, any ideas please?

[Jorge_Jaramillo]

Hi @stevehattCXSXP,

This are the parameters and its expressions:

The R-Pattern was defined like so:

And this is the result:

I hope this could help you out.

Regards,

Jorge Jaramillo

Software Engineer

[stevehattCXSXP]

Thanks, that looks what I am after. However, the issue I keep getting is that it won't allow me to input anything other than a numerical answer in the 2 yellow boxes. If I type number_holes the text stays red and then disappears when I hit return.

[Jorge_Jaramillo]

Hi,
Could you share in an image how are you parameters defined?
I believe you have issues with the units.

[stevehattCXSXP]

[Jorge_Jaramillo · Accepted solution]

Hi,

This is your problem:

Delete number_holes parameter and re-create it WITHOUT units.

[stevehattCXSXP]

thanks for everyone's help, I can see how it works now!