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Dynamic Rebar Standee

9 REPLIES 9
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Message 1 of 10
bbrems3K829
540 Views, 9 Replies

Dynamic Rebar Standee

I am trying to make a Rebar Standee Dynamic Block.

In simple form its a triangle.

The goal is to have the top angle stay at 45 degrees and the two sides get longer.

I was able to get them to stretch independently but need them to move together and be controlled from the center.

Please help. I have tired many of the solutions posted for triangles and none have worked.

9 REPLIES 9
Message 2 of 10
hwalker
in reply to: bbrems3K829

Try the attached

 

Howard Walker
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Message 3 of 10
bbrems3K829
in reply to: hwalker

Yes this is what I needed!

Can you please explain your process?

I tried to  create it and its not working.

 

Message 4 of 10
bbrems3K829
in reply to: hwalker

I also noticed the center point is not staying tangent to the legs.

Is there a way to keep it inline?

bbrems3K829_0-1653571777069.png

 

Message 5 of 10
hwalker
in reply to: bbrems3K829

@bbrems3K829 

 

Here I've updated the block.

If you look at all the stretch actions apart from stretch and stretch1 which are just used to stretch the horizontal line, you will see that they all have distance multipliers and angle offsets.

They all use the vertical distance as their base length and then stretch either slightly longer for the diagonals or shorter for the horizontal line.

Howard Walker
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Left Handed and Proud

Message 6 of 10
bbrems3K829
in reply to: hwalker

This is awesome!

Thank you!

 

Can you explain the math? 

How did you figure out the multiplier and angle offset?

Message 7 of 10
hwalker
in reply to: bbrems3K829

The Height of your vertical distance parameter is 7.75

The "Length" of one of the legs from where the vertical distance starts to the horizontal line is 8.38853955. Then all you need to do is 8.38853955/7.75 which will give you the 1.08 stretch for the angle leg multiplier

Similarly half of the distance of your horizontal line is 3.10660172 divide that by 7.75 and you get the .4 multiplier for the horizontal line.

I'm not to good with the angles, so it was a little trial and error after getting the angle of the "long leg" to work out what the angle offset needed to be for the two diagonal stretches

Howard Walker
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Message 8 of 10
bbrems3K829
in reply to: hwalker

Thank you so much for your help and explaining the solution.

It is much appreciated.

I am so thankful for this community. 

I always try to search and figure out the solution. 

I know when I'm stumped someone here knows the answer and is willing to help.

Thanks again, Beth  

Message 9 of 10
Libbya
in reply to: bbrems3K829

IMO, the easy way to find the angle offsets and the distance multipliers, is to use the built-in quickcalc from within the properties of the actions.  See screencast.

 

 

Message 10 of 10
bbrems3K829
in reply to: Libbya

Thank you!

This was very helpful

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