Creating a wire number that it is independent from the Bus.

[Anonymous]

Hello everyone,

I am making a ladder diagram, and I am trying to separate the wire number of the Bus(L1) from the wire that goes into the component. The software thinks of it as a single wire given that they are connected to the same bus, but physically(the real world) these wires will have different wire numbers, since the L1 that powers one component  will be a different wire from the L1 wire that goes to another component, even if they all meet to the same power distribution block upstream.

[Icemanau]

OK, the normal standard is that all wires that connect to each other, get treated as the same wire.

The alternative standard is to have each individual wire have a separate number.

To get the second standard, go to your Project Settings.

On the Wire Numbers tab, under Wire Number Options, there is a checkbox for 'On per wire basis'. Select that and ACADE will do what you want it to do in regards to the wire numbers.

Regards Brad

[Anonymous]

Thanks for the Reply,

That solution did not work, maybe I need to click something else as well, I attached two pictures, one showing the setting that I enabled to make sure I did what you said, and the other one so that you can see what happened. 

Thanks again

[Anonymous]

I figured it out, after clicking "per wire basis", one must insert TB's where the nodes are in the ladder

[pmccutcheon]

An old and dirty trick is to connect with a line not on a wire layer, say layer 0. The auto-numberer doesn't see this as a connection, so the bus and drop get distinct numbers. Downside is stuff like Scoot doesn't work well, as it is not a wire.

{Another place where you need distinct numbers is when you bond a transformer secondary. The GND wire has on number (GND) and the neutral something else}

[pmccutcheon]

newer versions of autocad support wire layers that aren't numbered. This might work better than the 
"layer 0" trick. 

[Anonymous]

Hi There.

You can achieve this without the use of extra terminals.