List transformation

[Browning_Zed]

Hello everyone,
This may be a simple task, but my knowledge is not enough to solve it.
How to get the string "\ nA \ nB \ nC \ nD" from the existing list '("A" "B" "C" "D")?

[Moshe-A]

@Browning_Zed ,

somting like this?  (un tested)

enjoy

moshe

(setq lst (mapcar
             '(lambda (s)
               (strcat "\\ n " s)
               )
            '("A" "B" "C" "D")
           )
)

[pbejse · Accepted solution]

---

@Browning_Zed wrote:

Hello everyone,
This may be a simple task, but my knowledge is not enough to solve it.
How to get the string "\ nA \ nB \ nC \ nD" from the existing list '("A" "B" "C" "D")?

---

it depends, if you need just the "\" you have to use "\\"

(setq lst '("A" "B" "C" "D"))
(substr (apply 'strcat (mapcar '(lambda (s)
               (strcat " \\ n" s)
               ) lst )) 2)

but for newline "\n" this is enough

(setq lst '("A" "B" "C" "D"))
(substr (apply 'strcat (mapcar '(lambda (s)
               (strcat " \n" s)
               ) lst )) 2)

Sorry about that, my bad 

[Sea-Haven]

An alternative method

(setq lst '("A" "B" "C" "D"))
(setq str "")
(foreach val lst
(setq str (strcat str " \n" val))
)