Autolisp function for log base 2?

[whgill01]

I'm looking for a function that will return the log base 2 of a number. For instance log2(128) should return 7. Thanks!

[whgill01 · Accepted solution]

Got it. log2(128) = (/ log 128) (log 2)) = 7

[whgill01 · Accepted solution]

That should be (/ (log 128) (log 2))